# C Exercises: Find the angle between (12:00 to 11:59) the hour hand and the minute hand of a clock

## C Basic Declarations and Expressions: Exercise-91 with Solution

Write a C program to find the angle between (12:00 to 11:59) the hour hand and the minute hand of a clock. The hour hand and the minute hand are always between 0 and 180 degrees.

For example, when it's 12 o'clock, the angle of the two hands is 0 while 3:00 is 45 degrees and 6:00 is 180 degrees.

**Sample Solution:**

**C Code:**

```
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int main()
{
int h, m; // Declare variables for hour and minute
double angle; // Declare variable for angle
const int num[13] = {0,30,60,90,120,150,180,210,240,270,300,330,0}; // Define an array of angles
printf("Input hour(h) and minute(m) (separated by a space):\n"); // Prompt user for input
scanf("%d %d",&h,&m); // Read input for hour and minute
angle = num[h] - m*5.5; // Calculate the angle based on the input values
if (angle < 0) // Ensure angle is positive
angle = -angle;
if (angle > 180) // Ensure angle is within 180 degrees
angle = 360 - angle;
if ( m < 10 )
printf("At %d:0%d the angle is %.1f degrees.\n",h,m,angle); // Print angle and time in format HH:MM
else
printf("The angle is %.1f degrees at %d:%d.\n",angle,h,m); // Print angle and time in format HH:MM
return 0; // Indicate successful execution of the program
}
```

Sample Output:

Input hour(h) and minute(m) (separated by a space): 3 0 At 3:00 the angle is 90.0 degrees. Input hour(h) and minute(m) (separated by a space): 6 15 The angle is 90.0 degrees at 6:15. Input hour(h) and minute(m) (separated by a space): 12 0 At 12:00 the angle is 0.0 degrees.

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