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C Exercises: Accept digit and display in the word

C Conditional Statement: Exercise-22 with Solution

Write a program in C to read any digit, display in the word.

Pictorial Presentation:

Accept digit and display in the word

Sample Solution:

C Code:

#include <stdio.h>
void main()
{
   int cdigit;

   printf("Input Digit(0-9) : ");
   scanf("%d",&cdigit);
   switch(cdigit)
   {
	 case 0:
	       printf("Zero\n");
	       break;
 
	 case 1:
	       printf("one\n");
	       break;
	case 2:
	       printf("Two\n");
	       break;
	case 3:
	       printf("Three\n");
	       break;
	case 4:
	       printf("Four\n");
	       break;
	case 5:
	       printf("Five\n");
	       break;
	case 6:
	       printf("Six\n");
	       break;
	case 7:
	       printf("Seven\n");
	       break;
	case 8:
	       printf("Eight\n");
	       break;
	case 9:
	       printf("Nine\n");
	       break;
	default:
	       printf("invalid digit. \nPlease try again ....\n");
	       break;
      }
}

Sample Output:

Input Digit(0-9) : 4                                                                                          
Four  

Flowchart:

Flowchart: A menu driven program for a simple calculator

C Programming Code Editor:

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Previous: Write a program in C to read any day number in integer and display day name in the word.
Next: Write a program in C to read any Month Number in integer and display Month name in the word.

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C Programming: Tips of the Day

Why do C and C++ compilers allow array lengths in function signatures when they're never enforced?

It is a quirk of the syntax for passing arrays to functions.

Actually it is not possible to pass an array in C. If you write syntax that looks like it should pass the array, what actually happens is that a pointer to the first element of the array is passed instead.

Since the pointer does not include any length information, the contents of your [] in the function formal parameter list are actually ignored.

Ref : https://bit.ly/3fhlvdH