# C Exercises: Display the value of an integer n is 1,0 and -1 for the value of an integer m

## C Conditional Statement: Exercise-6 with Solution

Write a C program to read the value of an integer m and display the value of n is 1 when m is larger than 0, 0 when m is 0 and -1 when m is less than 0.

**Pictorial Presentation:**

**Sample Solution**:

**C Code:**

```
#include <stdio.h>
void main()
{
int m,n;
printf("Input the value of m :");
scanf("%d",&m);
if(m!=0)
if(m>0)
n=1;
else
n=-1;
else
n=0;
printf("The value of m = %d \n",m);
printf("The value of n = %d \n",n);
}
```

Sample Output:

Input the value of m :-5 The value of m = -5 The value of n = -1

**Flowchart: **

**C Programming Code Editor:**

**Improve this sample solution and post your code through Disqus.**

**Previous:** Write a C program to read the age of a candiadte and detrermine whether it is eligible for casting his/her own vote.

**Next:** Write a C program to accept the height of a person in centimeter and categorize the person according to their height.

**What is the difficulty level of this exercise?**

Test your Programming skills with w3resource's quiz.

## C Programming: Tips of the Day

** What does (x ^ 0x1) != 0 mean?**

The XOR operation (x ^ 0x1) inverts bit 0. So the expression effectively means: if bit 0 of x is 0, or any other bit of x is 1, then the expression is true.

Conversely the expression is false if x == 1.

So the test is the same as:

if (x != 1)

and is therefore (arguably) unnecessarily obfuscated.

Ref :https://bit.ly/2NIisQM

**Weekly Trends**- Java Basic Programming Exercises
- SQL Subqueries
- Adventureworks Database Exercises
- C# Sharp Basic Exercises
- SQL COUNT() with distinct
- JavaScript String Exercises
- JavaScript HTML Form Validation
- Java Collection Exercises
- SQL COUNT() function
- SQL Inner Join
- JavaScript functions Exercises
- Python Tutorial
- Python Array Exercises
- SQL Cross Join
- C# Sharp Array Exercises

We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook