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C Exercises: Display first 10 natural numbers

C For Loop: Exercise-1 with Solution

Write a program in C to display the first 10 natural numbers.

Pictorial Presentation:

Display first 10 natural numbers

Sample Solution:

C Code:

#include <stdio.h>
void main()
{     
    int i;
	printf("The first 10 natural numbers are:\n");
	for (i=1;i<=10;i++)
	{      
		printf("%d ",i);
	}
printf("\n");
}

Sample Output: 

The first 10 natural numbers are:                                                                               
1 2 3 4 5 6 7 8 9 10

Flowchart:

Flowchart: Display first 10 natural numbers

Step wise execution of C program :

  • Green color means line that has just executed
  • Red color means next line to excute
  • Stack : a stack is an abstract data type that serves as a collection of elements.
Steps Code Stack Output
Step-1 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }

main
i(int): ?

Step-2 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): ?
Step-3 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): ?		 The first 10 natural numbers are:
Step-4 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 1 		The first 10 natural numbers are:
Step-5 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 1 		The first 10 natural numbers are:
1
Step-6 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 2 		The first 5 natural numbers are:
1
Step-7 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 2 		The first 5 natural numbers are:
1 2
Step-8 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 3 		The first 5 natural numbers are:
1 2
Step-9 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 3 		The first 5 natural numbers are:
1 2 3
Step-10 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 4 		The first 10 natural numbers are:
1 2 3
Step-11 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 4 		The first 10 natural numbers are:
1 2 3 4
Step-12 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 5 		The first 10 natural numbers are:
1 2 3 4
Step-13 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 5 		The first 10 natural numbers are:
1 2 3 4 5
Step-14 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 6 		The first 10 natural numbers are:
1 2 3 4 5
Step-15 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 6 		The first 10 natural numbers are:
1 2 3 4 5 6
Step-16 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 7 		The first 10 natural numbers are:
1 2 3 4 5 6
Step-17 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
 main
i(int): 7 		The first 10 natural numbers are:
1 2 3 4 5 6 7
Step-18 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 8 		The first 10 natural numbers are:
1 2 3 4 5 6 7
Step-19 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 8 		The first 10 natural numbers are:
1 2 3 4 5 6 7 8
Step-20 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 9 		The first 10 natural numbers are:
1 2 3 4 5 6 7 8
Step-21 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 9 		The first 10 natural numbers are: 1 2 3 4 5 6 7 8 9
Step-22 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 10 		The first 10 natural numbers are:
1 2 3 4 5 6 7 8 9
Step-23 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 10 		The first 10 natural numbers are:
1 2 3 4 5 6 7 8 9 10
Step-24 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 11		 The first 10 natural numbers are:
1 2 3 4 5 6 7 8 9 10
Step-25 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 11		 The first 10 natural numbers are:
1 2 3 4 5 6 7 8 9 10
Exit 
1 int main(){
2 int i;
3 printf("The first 10 natural numbers are:\n");
4 for (i=1;i<=10;i++)
5 {      
6 printf("%d ",i);
7 }
8 printf("\n");
9 return 0;
10 }
main
i(int): 11		 The first 10 natural numbers are:
1 2 3 4 5 6 7 8 9 10

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C Programming: Tips of the Day

Printing hexadecimal characters in C:

You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension.

Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your sample don't.

char    int
c0 -> ffffffc0
80 -> ffffff80
61 -> 00000061
Here's a solution: 
char ch = 0xC0;
printf("%x", ch & 0xff);

This will mask out the upper bits and keep only the lower 8 bits that you want.

Ref : https://bit.ly/3vOLizM