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C Exercises: Convert an octal number into binary

C For Loop: Exercise-54 with Solution

Write a program in C to convert an octal number into binary.

Pictorial Presentation:

Convert an octal number into binary

Sample Solution:

C Code:

#include <stdio.h>
#include <math.h>

void main()
{


     long int n1, n5,p=1;
     long int dec=0,i=1,j,d;
     long int binno=0;


     printf("\n\nConvert Octal to Binary:\n ");
     printf("-------------------------\n");

	printf("Input an octal number (using digit 0 - 7) :");
	scanf("%ld",&n1);
	n5=n1;



	for (j=n1;j>0;j=j/10)
	{  
          d = j % 10;
            if(i==1)
                  p=p*1;
            else
                 p=p*8;

	   dec=dec+(d*p);
	   i++;
	}

/*------------------------------------------------------------------------------*/
     i=1;

      for(j=dec;j>0;j=j/2)
       {
        binno=binno+(dec % 2)*i;
        i=i*10;
        dec=dec/2;
       }
     
        printf("\nThe Octal Number : %ld\nThe equivalent Binary  Number : %ld \n\n",n5,binno);

}

Sample Output:

Convert Octal to Binary:                                                                                      
 -------------------------                                                                                    
Input an octal number (using digit 0 - 7) :57                                                                 
                                                                                                              
The Octal Number : 57                                                                                         
The equivalent Binary  Number : 101111 

Flowchart:

Flowchart : Convert octal number into binary.

C Programming Code Editor:

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Previous: Write a program in C to convert a binary number to octal.
Next: Write a program in C to convert a decimal number to hexadecimal.

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C Programming: Tips of the Day

Printing hexadecimal characters in C:

You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension.

Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your sample don't.

char    int
c0 -> ffffffc0
80 -> ffffff80
61 -> 00000061
Here's a solution:
char ch = 0xC0;
printf("%x", ch & 0xff);

This will mask out the upper bits and keep only the lower 8 bits that you want.

Ref : https://bit.ly/3vOLizM