C Exercises: Find Disarium numbers between 1 to 1000

C Numbers: Exercise-16 with Solution

Write a program in C to find Disarium numbers between 1 to 1000.

Sample Solution:

C Code:

# include <stdio.h>
# include <math.h>
# include <stdlib.h>
# include <stdbool.h>

int DigiCount(int n)
    int ctr_digi = 0;
    int tmpx = n;
    while (tmpx)
        tmpx = tmpx/10;
    return ctr_digi;
bool chkDisarum(int n)
    int ctr_digi = DigiCount(n);
    int s = 0; 
    int x = n;
    int pr;
    while (x)
        pr = x % 10;
        s = s + pow(pr, ctr_digi--);
        x = x/10;
    return (s == n);
int main()

int i;
	printf("\n\n Find Disarium Numbers between 1 to 1000: \n");
	printf(" ---------------------------------------------\n");
	printf(" The Disarium numbers are: \n");
    if( chkDisarum(i))
		printf("%d ",i); 

Sample Output:

 The Disarium numbers are:                                                                                    
1 2 3 4 5 6 7 8 9 89 135 175 518 598 

Pictorial Presentation:

C programming: Find Disarium numbers between 1 to 1000.


Flowchart: Find Disarium numbers between 1 to 1000.

C Programming Code Editor:

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C Programming: Tips of the Day

Why do C and C++ compilers allow array lengths in function signatures when they're never enforced?

It is a quirk of the syntax for passing arrays to functions.

Actually it is not possible to pass an array in C. If you write syntax that looks like it should pass the array, what actually happens is that a pointer to the first element of the array is passed instead.

Since the pointer does not include any length information, the contents of your [] in the function formal parameter list are actually ignored.

Ref : https://bit.ly/3fhlvdH