C Exercises: Find Pronic Number between 1 to 1000
C Numbers: Exercise-20 with Solution
Write a program in C to find Pronic Number between 1 to 1000.
Sample Solution:
C Code:
# include <stdio.h>
# include <stdlib.h>
int main()
{
int prno,i,n,flg;
printf("\n\n Find the Pronic Numbers between 1 to 1000: \n");
printf(" -----------------------------------------------\n");
printf(" The Pronic numbers are: \n");
for(prno=1;prno<=1000;prno++)
{
flg=0;
for(i=1;i<=prno;i++)
{
if(i*(i+1)==prno)
{
flg=1;
break;
}
}
if(flg==1)
{
printf("%d ",prno);
}
}
printf("\n");
}
Sample Output:
The Pronic numbers are: 2 6 12 20 30 42 56 72 90 110 132 156 182 210 240 272 306 342 380 420 462 506 552 600 650
702 756 812 870 930 992
Pictorial Presentation:
Flowchart:

C Programming Code Editor:
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Previous: Write a program in C to check whether a number is a Pronic Number or Heteromecic Number or not.
Next: Write a program in C to check if a number is Authomorphic or not.
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C Programming: Tips of the Day
Why do C and C++ compilers allow array lengths in function signatures when they're never enforced?
It is a quirk of the syntax for passing arrays to functions.
Actually it is not possible to pass an array in C. If you write syntax that looks like it should pass the array, what actually happens is that a pointer to the first element of the array is passed instead.
Since the pointer does not include any length information, the contents of your [] in the function formal parameter list are actually ignored.
Ref : https://bit.ly/3fhlvdH
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