C Exercises: Add two numbers using call by reference
C Pointer : Exercise-5 with Solution
Write a program in C to add numbers using call by reference.
Pictorial Presentation:

Sample Solution:
C Code:
#include <stdio.h>
long addTwoNumbers(long *, long *);
int main()
{
long fno, sno, sum;
printf("\n\n Pointer : Add two numbers using call by reference:\n");
printf("-------------------------------------------------------\n");
printf(" Input the first number : ");
scanf("%ld", &fno);
printf(" Input the second number : ");
scanf("%ld", &sno);
sum = addTwoNumbers(&fno, &sno);
printf(" The sum of %ld and %ld is %ld\n\n", fno, sno, sum);
return 0;
}
long addTwoNumbers(long *n1, long *n2)
{
long sum;
sum = *n1 + *n2;
return sum;
}
Sample Output:
Pointer : Add two numbers using call by reference: ------------------------------------------------------- Input the first number : 5 Input the second number : 6 The sum of 5 and 6 is 11
Flowchart:

C Programming Code Editor:
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C Programming: Tips of the Day
How to format strings using printf() to get equal length in the output?
You can specify a width on string fields, e.g.
printf("%-20s", "initialization...");
And then whatever's printed with that field will be blank-padded to the width you indicate.
The - left-justifies your text in that field.
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