C Programming: Check whether a character is Hexadecimal Digit or not

C String: Exercise-23 with Solution

Write a program in C to check whether a character is a Hexadecimal Digit or not.

Sample Solution:

C Code:

#include<stdio.h>
#include<ctype.h>

int main() {
    char TestChar; // Variable to store the input character

    printf("\n Check whether a character is Hexadecimal Digit or not :\n");
    printf("-------------------------------------------------------\n");
    printf(" Input a character : "); // Prompt user to input a character
    scanf("%c", &TestChar); // Read a character from the user

    // Check if the entered character is a hexadecimal digit
    if (isxdigit(TestChar)) {
        printf(" The entered character is a hexadecimal digit. \n"); // Display message if it is a hexadecimal digit
    } else {
        printf(" The entered character is not a hexadecimal digit. \n"); // Display message if it is not a hexadecimal digit
    }

    return 0; // Return 0 to indicate successful execution of the program
}

Sample Output:

 Check whether a character is Hexadecimal Digit or not :
-------------------------------------------------------
 Input a character : 7
 The entered character is a hexadecimal digit.

Flowchart :

C Programming Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a program in C to convert a string to lowercase.
Next: Write a program in C to check whether a letter is uppercase or not.