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C Exercises: Print only the string before new line character

C String: Exercise-27 with Solution

Write a program in C to print only the string before new line character.

Note: isprint() will only print line one, because the newline character is not printable.

Sample Solution:

C Code:

#include<stdio.h>
#include<ctype.h>

int main()
{
	int ctr=0;
	char str[]=" The quick brown fox \n jumps over the \n lazy dog. \n";	
	printf("\n Print only the string before new line character :\n");  
    printf("----------------------------------------------------\n");	
	while (isprint(str[ctr]))
	{
		putchar (str[ctr]);
		ctr++;
	}
	printf("\n\n");
	return 0;
}

Sample Output:

 Print only the string before new line character :
----------------------------------------------------
 The quick brown fox

Flowchart :

Flowchart: Print only the string before new line character

C Programming Code Editor:

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Next: Write a program in C to check whether a letter is lowercase or not.

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C Programming: Tips of the Day

How to measure time in milliseconds using ANSI C?

There is no ANSI C function that provides better than 1 second time resolution but the POSIX function gettimeofday provides microsecond resolution. The clock function only measures the amount of time that a process has spent executing and is not accurate on many systems.

You can use this function like this:

structtimevaltval_before, tval_after, tval_result;

gettimeofday(&tval_before, NULL);

// Some code you want to time, for example:
sleep(1);

gettimeofday(&tval_after, NULL);

timersub(&tval_after, &tval_before, &tval_result);

printf("Time elapsed: %ld.%06ld\n", (long int)tval_result.tv_sec, (long int)tval_result.tv_usec);

This returns Time elapsed: 1.000870 on my machine.

Ref : https://bit.ly/3lpwoMn