C++ Exercises: Find the two repeating elements in a given array of integers

C++ Array: Exercise-21 with Solution

Write a C++ program to find the two repeating elements in a given array of integers.

Sample Solution:

C++ Code :

#include <iostream> // Header file for input/output stream
using namespace std; // Using the standard namespace

int main()
{
    int nums[] = {1, 2, 3, 5, 5, 7, 8, 8, 9, 9, 2}; // Declaration and initialization of an integer array
    int i, j; // Declaration of loop control variables
    int size = sizeof(nums) / sizeof(nums[0]); // Calculate the number of elements in the array
    cout << "Original array: ";
    for (i = 0; i < size; i++) 
        cout << nums[i] << " "; // Output each element of the original array

    cout << "\nRepeating elements: "; // Output label for repeating elements
    for (i = 0; i < size; i++) // Outer loop to iterate through each element in the array
        for (j = i + 1; j < size; j++) // Inner loop to compare each element with subsequent elements
            if (nums[i] == nums[j]) // Check if current element is equal to any other element in the array
                cout << nums[i] << " "; // Output the repeating element

    return 0; // Return 0 to indicate successful execution
}

Sample Output:

Original array: 1 2 3 5 5 7 8 8 9 9 2 
Repeating elements: 2 5 8 9 

Flowchart:

C++ Code Editor:

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