﻿ C++ : Find the two repeating elements in a array of integers

# C++ Exercises: Find the two repeating elements in a given array of integers

## C++ Array: Exercise-21 with Solution

Write a C++ program to find the two repeating elements in a given array of integers.

Sample Solution:

C++ Code :

``````#include <iostream>
using namespace std;

int main()
{
int nums[] = {1, 2, 3, 5, 5, 7, 8, 8, 9, 9, 2};
int i, j;
int size = sizeof(nums)/sizeof(nums[0]);
cout << "Original array: ";
for (i = 0; i < size; i++)
cout << nums[i] <<" ";
cout  << "\nRepeating elements: ";
for(i = 0; i < size; i++)
for(j = i+1; j < size; j++)
if(nums[i] == nums[j])
cout <<  nums[i] << " ";

return 0;

}
``````

Sample Output:

```Original array: 1 2 3 5 5 7 8 8 9 9 2
Repeating elements: 2 5 8 9
```

Flowchart:

C++ Code Editor:

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## C++ Programming: Tips of the Day

Can I assume (bool)true == (int)1 for any C++ compiler?

According to the standard, you should be safe with that assumption. The C++ bool type has two values - true and false with corresponding values 1 and 0.

The thing to watch about for is mixing bool expressions and variables with BOOL expression and variables. The latter is defined as FALSE = 0 and TRUE != FALSE, which quite often in practice means that any value different from 0 is considered TRUE.

A lot of modern compilers will actually issue a warning for any code that implicitly tries to cast from BOOL to bool if the BOOL value is different than 0 or 1

Ref: https://bit.ly/3PWhs5N