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C++ Exercises: Compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x

C++ Basic Algorithm: Exercise-51 with Solution

Write a C++ program to compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x. If the sum has more digits than x then return x without y.

Sample Solution:

C++ Code :

#include <iostream>
#include<string>

using namespace std;

int test(int x, int y)
        {
           return to_string(x + y).length() > to_string(x).length() ? x : x + y;
        }
        
int main() 
 {
  cout << test(4, 5) << endl;  
  cout << test(7, 4) << endl;  
  cout << test(10, 10) << endl;  
  return 0;    
}

Sample Output:

9
7
20

Pictorial Presentation:

C++ Basic Algorithm Exercises: Compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x.

Flowchart:

Flowchart: Compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x.

C++ Code Editor:

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Previous: Write a C++ program to check two given integers, each in the range 10..99. Return true if a digit appears in both numbers, such as the 3 in 13 and 33.
Next: Write a C++ program to compute the sum of three given integers. If the two values are same return the third value.

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