C++ Exercises: Compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x

C++ Basic Algorithm: Exercise-51 with Solution

Write a C++ program to compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x. If the sum has more digits than x, return x without y.

Sample Solution:

C++ Code :

#include <iostream>
#include <string> // Included library for string handling

using namespace std;

// Function 'test' takes two integers (x, y) as parameters
int test(int x, int y)
{
    // Converts the sum of x and y to a string and checks if its length
    // is greater than the length of x converted to a string
    // Returns x if the length of x is smaller than the length of x + y,
    // otherwise returns the sum of x and y
    return to_string(x + y).length() > to_string(x).length() ? x : x + y;
}

int main() 
{
    // Testing the 'test' function with different sets of numbers
    cout << test(4, 5) << endl;
    cout << test(7, 4) << endl;
    cout << test(10, 10) << endl;

    return 0;    
}

Sample Output:

9
7
20

Visual Presentation:

Flowchart:

C++ Code Editor:

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