﻿ C++ : Number, sum of all integer divisible by 9 in a range

C++ Exercises: Find the number and sum of all integer between 100 and 200 which are divisible by 9

C++ For Loop: Exercise-28 with Solution

Write a program in C++ to find the number and sum of all integers between 100 and 200 which are divisible by 9.

Visual Presentation:

Sample Solution:-

C++ Code :

``````#include <iostream> // Including input-output stream header

using namespace std; // Using standard namespace to avoid writing std::

int main() // Start of the main function
{
int i, sum = 0; // Declaration of integer variables 'i' (loop counter), 'sum' (stores the sum of numbers)

cout << "\n\n Find the number and sum of all integers between 100 and 200, divisible by 9:\n"; // Displaying a message on the console
cout << "--------------------------------------------------------------------------------\n";
cout << " Numbers between 100 and 200, divisible by 9: " << endl; // Displaying a message indicating the range of numbers

for (i = 101; i < 200; i++) // Loop to iterate through numbers between 101 and 199 (inclusive)
{
if (i % 9 == 0) // Checking if the number is divisible by 9
{
cout << " " << i; // Displaying the number if it is divisible by 9
sum += i; // Adding the number to the sum
}
}

cout << "\n The sum : " << sum << endl; // Displaying the sum of the numbers divisible by 9
}
``````

Sample Output:

``` Find the number and sum of all integer between 100 and 200, divisible by 9:
--------------------------------------------------------------------------------
Numbers between 100 and 200, divisible by 9:
108 117 126 135 144 153 162 171 180 189 198
The sum : 1683
```

Flowchart:

C++ Code Editor: