﻿ C++ : Check if a number is an Armstrong number or not

# C++ Exercises: Check whether a given number is an Armstrong number or not

## C++ Numbers: Exercise-43 with Solution

Write a C++ program to check whether a given number is an Armstrong number or not.

/*When the sum of the cube of the individual digits of a number
is equal to that number, the number is called Armstrong number. For example 153.
Sum of its divisor is 13 + 53;+ 33; = 1+125+27 = 153*/

Sample Solution:

C++ Code:

``````#include <iostream>
using namespace std;

int main()
{
int num, r, sum = 0, temp;
// Prompt user for input
cout << "\n\n Check whether a given number is an Armstrong number or not :\n";
cout << "-----------------------------------------------------------------\n";
cout << " Input a number: ";
cin >> num; // Input the number to check

// Loop to calculate the sum of cubes of digits
for (temp = num; num != 0; num = num / 10)
{
r = num % 10; // Extract the digit
sum = sum + (r * r * r); // Cube each digit and add to sum
}

// Check if the sum of cubes of digits equals the original number
if (sum == temp)
cout << temp << " is an Armstrong number." << endl; // Print if it's an Armstrong number
else
cout << temp << " is not an Armstrong number." << endl; // Print if it's not an Armstrong number
}
``````

Sample Output:

```Check whether a given number is an Armstrong number or not:
-------------------------------------------------------
Input a number: 153
153 is an Armstrong number
```

Flowchart:

C++ Code Editor: