C++ Exercises: Check whether a number is a Strong Number or not

C++ Numbers: Exercise-45 with Solution

Write a C++ program to check whether a number is a Strong Number or not.

Sample Solution:

C++ Code:

#include <iostream>
using namespace std;

int main()
{
    int i, n, n1, s1 = 0, j; // Declare variables for iteration and sum initialization
    long fact; // Declare a variable to store factorial

    // Prompt the user to input a number to check if it is a Strong number
    cout << "\n\n Check whether a number is Strong Number or not:\n";
    cout << "----------------------------------------------------\n";
    cout << " Input a number to check whether it is a Strong number: ";
    cin >> n; // Take user input

    n1 = n; // Store the original number in n1

    // Loop through the digits of the number to calculate the sum of factorials
    for (j = n; j > 0; j = j / 10) {
        fact = 1; // Initialize factorial to 1 for each digit

        // Calculate factorial for each digit
        for (i = 1; i <= j % 10; i++) {
            fact = fact * i; // Multiply each digit's factorial
        }

        s1 = s1 + fact; // Accumulate the sum of factorials for each digit
    }

    // Check if the sum of factorials of digits is equal to the original number
    if (s1 == n1) {
        cout << n1 << " is a Strong number." << endl; // Print if the number is a Strong number
    }
    else {
        cout << n1 << " is not a Strong number." << endl; // Print if the number is not a Strong number
    }
}

Sample Output:

Check whether a number is Strong Number or not:                                                
 -------------------------------------------------------                                             
 Input a number to check whether it is Strong number: 24 
24 is not a Strong number

Flowchart:

C++ Code Editor:

Contribute your code and comments through Disqus.

Previous: Write a program in C++ to find the Armstrong number for a given range of number.
Next: C++ Sorting and Searching Exercises Home