C#: Print all unique elements of an array

C# Sharp Array: Exercise-6 with Solution

Write a program in C# Sharp to print all unique elements in an array.

Sample Solution:-

C# Sharp Code:

using System;

public class Exercise6
{
    public static void Main()
    {
        int n, ctr = 0;  // Declaration of variables 'n' (number of elements) and 'ctr' (counter)
        int[] arr1 = new int[100];  // Declaration of an integer array 'arr1' with size 100
        int i, j, k;  // Declaration of loop control variables 'i', 'j', and 'k'

        // Display a message to print all unique elements of an array
        Console.Write("\n\nPrint all unique elements of an array:\n");
        Console.Write("------------------------------------------\n");

        Console.Write("Input the number of elements to be stored in the array :");
        n = Convert.ToInt32(Console.ReadLine());  // Read the number of elements from the user and store it in 'n'

        Console.Write("Input {0} elements in the array :\n", n);  // Prompt the user to input 'n' elements
        for (i = 0; i < n; i++)
        {
            Console.Write("element - {0} : ", i);
            arr1[i] = Convert.ToInt32(Console.ReadLine());  // Read user input and store it in the array 'arr1'
        }

        // Checking for unique elements in the array
        Console.Write("\nThe unique elements found in the array are : \n");
        for (i = 0; i < n; i++)
        {
            ctr = 0;  // Reset the counter for each element in the array

            // Check for duplicates before the current position in the array
            for (j = 0; j < i - 1; j++)
            {
                // Increment the counter if a duplicate is found
                if (arr1[i] == arr1[j])
                {
                    ctr++;
                }
            }

            // Check for duplicates after the current position in the array
            for (k = i + 1; k < n; k++)
            {
                // Increment the counter if a duplicate is found
                if (arr1[i] == arr1[k])
                {
                    ctr++;
                }

                // Skip if duplicate numbers are next to each other
                if (arr1[i] == arr1[i + 1])
                {
                    i++;  // Increment 'i' to skip the next element
                }
            }

            // Print the value if it's unique (counter remains 0)
            if (ctr == 0)
            {
                Console.Write("{0} ", arr1[i]);
            }
        }

        Console.Write("\n\n");  // Extra newline for formatting
    }
}

Sample Output:

Print all unique elements of an array:
------------------------------------------
Input the number of elements to be stored in the array :2
Input 2 elements in the array :
element - 0 : 2
element - 1 : 4

The unique elements found in the array are : 
2 4

Flowchart:

C# Sharp Code Editor:

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