C#: Shift an element in left direction and return a new array

C# Sharp Basic Algorithm: Exercise-127 with Solution

Write a C# Sharp program to shift an element left and return an array.

Visual Presentation:

Sample Solution:

C# Sharp Code:

using System; // Importing the System namespace

namespace exercises // Defining a namespace called 'exercises'
{
    class Program // Defining a class named 'Program'
    {
        static void Main(string[] args) // The entry point of the program
        {               
            // Calling the 'test' method with a given integer array and storing the returned array in 'item'
            int[] item = test(new[] { 10, 20, -30, -40, 50 }); 

            // Outputting the elements of the new array after shifting
            Console.Write("New array: "); 
            foreach (var i in item) // Looping through each element in the 'item' array
            {
                Console.Write(i.ToString() + " "); // Outputting each element followed by a space
            }     
        }               

        // Method to shift elements in an array to the left
        static int[] test(int[] numbers)
        {
            int size = numbers.Length; // Storing the length of the input array

            // Creating a new array to hold the shifted elements
            int[] shiftNums = new int[size];

            // Looping through each element of the input array
            for (int i = 0; i < size; i++)
            {
                // Shifting the elements to the left using modulo operation to handle circular shifting
                shiftNums[i] = numbers[(i + 1) % size];
            }

            return shiftNums; // Returning the new array with shifted elements
        }    
    } 
}

Sample Output:

New array: 20 -30 -40 50 10

Flowchart:

C# Sharp Code Editor:

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