C#: Check which number is nearest to the value 100 among two given integers

C# Sharp Basic Algorithm: Exercise-19 with Solution

Write a C# Sharp program to check which number is closest to 100 among two given integers. Return 0 if the two numbers are equal.

Visual Presentation 1:

Visual Presentation 2:

Sample Solution:

C# Sharp Code:

using System;

// Namespace declaration
namespace exercises
{
    // Class declaration
    class Program
    {
        // Main method - entry point of the program
        static void Main(string[] args)
        {
            // Displaying the output of the 'test' method with different integer values
            Console.WriteLine(test(78, 95));   // Output: 95
            Console.WriteLine(test(95, 95));   // Output: 0
            Console.WriteLine(test(99, 70));   // Output: 99
            Console.ReadLine();                // Keeping the console window open
        }

        // Method to compare two integers and return the closest to 100
        public static int test(int x, int y)
        {
            // Constant integer 'n' is assigned the value 100
            const int n = 100;

            // Calculate the absolute difference between 'x' and 'n'
            var val = Math.Abs(x - n);

            // Calculate the absolute difference between 'y' and 'n'
            var val2 = Math.Abs(y - n);

            // Check if the differences are equal; if true, return 0 as both 'x' and 'y' are equidistant from 100
            // Otherwise, return the number that is closer to 100 (the one with the smaller absolute difference)
            return val == val2 ? 0 : (val < val2 ? x : y);
        }
    }
}

Sample Output:

95
0
99

Flowchart:

C# Sharp Code Editor:

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