C#: Check whether three given numbers are in strict increasing order
C# Sharp Basic Algorithm: Exercise-49 with Solution
Strictly Increasing or Equal if Flag True
Write a C# Sharp program to check if three given numbers are in strict increasing order.
For example, 4 7 15, or 45, 56, 67, but not 4 ,5, 8 or 6, 6, 8. However, if a fourth parameter is true, equality is allowed, such as 6, 6, 8 or 7, 7, 7.
Visual Presentation:
Sample Solution:-
C# Sharp Code:
using System;
using System.Linq;
namespace exercises
{
// Class declaration
class Program
{
// Main method - entry point of the program
static void Main(string[] args)
{
// Calling the 'test' method with different integer values and a boolean flag, and printing the results
Console.WriteLine(test(1, 2, 3, false)); // Output: True (since flag is false, checks strict ascending order)
Console.WriteLine(test(1, 2, 3, true)); // Output: True (since flag is true, checks non-strict ascending order)
Console.WriteLine(test(10, 2, 30, false)); // Output: False (since flag is false, checks strict ascending order)
Console.WriteLine(test(10, 10, 30, true)); // Output: True (since flag is true, checks non-strict ascending order)
Console.ReadLine(); // Keeping the console window open
}
// Method to check the order of integers based on the flag value
public static bool test(int x, int y, int z, bool flag)
{
// If flag is true, checks for non-strict ascending order (x <= y <= z)
// If flag is false, checks for strict ascending order (x < y < z)
return flag ? x <= y && y <= z : x < y && y < z;
}
}
}
Sample Output:
True True False True
Flowchart:
C# Sharp Code Editor:
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