C#: Display the number in reverse order

C# Sharp For Loop: Exercise-37 with Solution

Write a program in C# Sharp to display a number in reverse order.

Visual Presentation:

Sample Solution:

C# Sharp Code:

using System;  // Importing necessary namespace

public class Exercise37  // Declaration of the Exercise37 class
{  
    public static void Main()  // Main method, entry point of the program
    {
        int num, r, sum = 0, t;  // Declaration of variables

        Console.Write("\n\n");  // Displaying new lines
        Console.Write("Display the number in reverse order:\n");  // Displaying the purpose of the program
        Console.Write("--------------------------------------\n\n");  // Displaying a separator and new lines

        Console.Write("Input a number: ");  // Prompting the user to input a number
        num = Convert.ToInt32(Console.ReadLine());  // Reading the number entered by the user

        for (t = num; t != 0; t = t / 10)  // Loop to reverse the number
        {
            r = t % 10;  // Extracting the last digit of the number
            sum = sum * 10 + r;  // Reversing the number by storing each digit sequentially
        }

        Console.Write("The number in reverse order is : {0} \n", sum);  // Displaying the number in reverse order
    }
}

Sample Output:

Display the number in reverse order:                                                                        
--------------------------------------                                                                      
Input a number: 25                                                                                          
The number in reverse order is : 52  

Flowchart:

C# Sharp Code Editor:

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