C#: Find the number and sum of all integer between 100 and 200, divisible by 9

Last update on December 20 2024 12:41:08 (UTC/GMT +8 hours)

Write a C# Sharp program to find the number and sum of all integers between 100 and 200 divisible by 9.

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Sample Solution:

C# Sharp Code:

using System;  // Importing necessary namespace

public class Exercise39  // Declaration of the Exercise39 class
{  
    public static void Main()  // Main method, entry point of the program
    {
        int i, sum = 0;  // Declaration of variables: 'i' for looping, 'sum' for storing the sum

        Console.Write("\n\n");  // Displaying new lines
        Console.Write("Find the number and sum of all integers between 100 and 200, divisible by 9:\n");  // Displaying the purpose of the program
        Console.Write("-----------------------------------------------------------------------------\n\n");  // Displaying a separator and new lines

        Console.Write("Numbers between 100 and 200, divisible by 9 : \n");  // Displaying the range of numbers
        for (i = 101; i < 200; i++)  // Loop through the range from 101 to 199
        {
            if (i % 9 == 0)  // Checking if the number is divisible by 9
            {
                Console.Write("{0}  ", i);  // Displaying the number divisible by 9
                sum += i;  // Adding the number to the 'sum' variable
            }
        }
        Console.Write("\n\nThe sum : {0} \n", sum);  // Displaying the total sum of numbers divisible by 9
    }
}

Sample Output:

Find the number and sum of all integer between 100 and 200, divisible by 9:                                 
-----------------------------------------------------------------------------                               
Numbers between 100 and 200, divisible by 9 :                                                               
108  117  126  135  144  153  162  171  180  189  198                                                       
The sum : 1683 

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