﻿ C# - Count and sum all integers divisible by 9

# C#: Find the number and sum of all integer between 100 and 200, divisible by 9

## C# Sharp For Loop: Exercise-39 with Solution

Write a C# Sharp program to find the number and sum of all integers between 100 and 200 divisible by 9.

Visual Presentation:

Sample Solution:

C# Sharp Code:

``````using System;  // Importing necessary namespace

public class Exercise39  // Declaration of the Exercise39 class
{
public static void Main()  // Main method, entry point of the program
{
int i, sum = 0;  // Declaration of variables: 'i' for looping, 'sum' for storing the sum

Console.Write("\n\n");  // Displaying new lines
Console.Write("Find the number and sum of all integers between 100 and 200, divisible by 9:\n");  // Displaying the purpose of the program
Console.Write("-----------------------------------------------------------------------------\n\n");  // Displaying a separator and new lines

Console.Write("Numbers between 100 and 200, divisible by 9 : \n");  // Displaying the range of numbers
for (i = 101; i < 200; i++)  // Loop through the range from 101 to 199
{
if (i % 9 == 0)  // Checking if the number is divisible by 9
{
Console.Write("{0}  ", i);  // Displaying the number divisible by 9
sum += i;  // Adding the number to the 'sum' variable
}
}
Console.Write("\n\nThe sum : {0} \n", sum);  // Displaying the total sum of numbers divisible by 9
}
}
```
```

Sample Output:

```Find the number and sum of all integer between 100 and 200, divisible by 9:
-----------------------------------------------------------------------------
Numbers between 100 and 200, divisible by 9 :
108  117  126  135  144  153  162  171  180  189  198
The sum : 1683
```

Flowchart:

C# Sharp Code Editor: