C#: Reverse an integer and add with the original number

C# Sharp String: Exercise-59 with Solution

Write a C# Sharp program to reverse a positive integer and add the reversed number to the original number.

Sample Data:
(456) - > 456654
(-123) -> "Input a positive number."
(10000) -> 1000000001

Sample Solution-1:

C# Sharp Code:

using System;
using System.Linq;
namespace exercises
{
    class Program
    {
        static void Main(string[] args)
        {

            int n = 567;
            Console.WriteLine("Original number: " + n);
            Console.WriteLine("Reverse the said integer and add with the original number-");
            Console.WriteLine(test(n));
            n = -123;
            Console.WriteLine("\nOriginal number: " + n);
            Console.WriteLine("Reverse the said integer and add with the original number-");
            Console.WriteLine(test(n));
            n = 10000;
            Console.WriteLine("\nOriginal number: " + n);
            Console.WriteLine("Reverse the said integer and add with the original number-");
            Console.WriteLine(test(n));
        }

        public static string test(int n)

        {
            if (n > 0)
            {
                return n + new string(n.ToString().Reverse().ToArray());
            }
            return "Input a positive number.";
        }
    }
}

Sample Output:

Original number: 567
Reverse the said integer and add with the original number-
567765

Original number: -123
Reverse the said integer and add with the original number-
Input a positive number.

Original number: 10000
Reverse the said integer and add with the original number-
1000000001

Flowchart :

Sample Solution-2:

C# Sharp Code:

using System;
using System.Linq;
namespace exercises
{
    class Program
    {
        static void Main(string[] args)
        {

            int n = 567;
            Console.WriteLine("Original number: " + n);
            Console.WriteLine("Reverse the said integer and add with the original number-");
            Console.WriteLine(test(n));
            n = -123;
            Console.WriteLine("\nOriginal number: " + n);
            Console.WriteLine("Reverse the said integer and add with the original number-");
            Console.WriteLine(test(n));
            n = 10000;
            Console.WriteLine("\nOriginal number: " + n);
            Console.WriteLine("Reverse the said integer and add with the original number-");
            Console.WriteLine(test(n));
        }

        public static string test(int n)

        {
            if (n > 0)
            {
                return n.ToString() + string.Concat(n.ToString().Reverse());
            }
            return "Input a positive number.";
        }
    }
}

Sample Output:

Original number: 567
Reverse the said integer and add with the original number-
567765

Original number: -123
Reverse the said integer and add with the original number-
Input a positive number.

Original number: 10000
Reverse the said integer and add with the original number-
1000000001

Flowchart :

C# Sharp Code Editor:

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