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Java Array Exercises: Sort a numeric array and a string array

Java Array: Exercise-1 with Solution

Write a Java program to sort a numeric array and a string array.

Pictorial Presentation:

Java Array Exercises:  Sort a numeric array and a string array

Sample Solution:

Java Code:

import java.util.Arrays; 
public class Exercise1 {
public static void main(String[] args){   
    
    int[] my_array1 = {
            1789, 2035, 1899, 1456, 2013, 
            1458, 2458, 1254, 1472, 2365, 
            1456, 2165, 1457, 2456};
            
    String[] my_array2 = {
            "Java",
			
            "Python",
            "PHP",
            "C#",
            "C Programming",
            "C++"
        };        
    System.out.println("Original numeric array : "+Arrays.toString(my_array1));
    Arrays.sort(my_array1);
    System.out.println("Sorted numeric array : "+Arrays.toString(my_array1));
    
    System.out.println("Original string array : "+Arrays.toString(my_array2));
    Arrays.sort(my_array2);
    System.out.println("Sorted string array : "+Arrays.toString(my_array2));
    }
}

Sample Output:

Original numeric array : [1789, 2035, 1899, 1456, 2013, 1458, 2458, 1254, 1472, 2365, 1456, 2165, 1457, 2456] 
Sorted numeric array : [1254, 1456, 1456, 1457, 1458, 1472, 1789, 1899, 2013, 2035, 2165, 2365, 2456, 2458]   
Original string array : [Java, Python, PHP, C#, C Programming, C++]                                           
Sorted string array : [C Programming, C#, C++, Java, PHP, Python] 

Flowchart:

Flowchart: Java Array Exercises: Sort a numeric array and a string array

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Java Code Editor:

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Java: Tips of the Day

Different between parseInt() and valueOf() in java?

Well, the API for Integer.valueOf(String) does indeed say that the String is interpreted exactly as if it were given to Integer.parseInt(String). However, valueOf(String) returns a new Integer() object whereas parseInt(String) returns a primitive int.

If you want to enjoy the potential caching benefits of Integer.valueOf(int), you could also use this eyesore:

Integer k = Integer.valueOf(Integer.parseInt("123"))

Now, if what you want is the object and not the primitive, then using valueOf(String) may be more attractive than making a new object out of parseInt(String) because the former is consistently present across Integer, Long, Double, etc.

Ref: https://bit.ly/3vRuIPY