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Java Array Exercises: Reverse an array of integer values

Java Array: Exercise-11 with Solution

Write a Java program to reverse an array of integer values.

Pictorial Presentation:

Java Array Exercises: Reverse an array of integer values

Sample Solution:

Java Code:

import java.util.Arrays; 
public class Exercise11 {
public static void main(String[] args){   
    int[] my_array1 = {
            1789, 2035, 1899, 1456, 2013, 
            1458, 2458, 1254, 1472, 2365, 
            1456, 2165, 1457, 2456};
  System.out.println("Original array : "+Arrays.toString(my_array1));  
   for(int i = 0; i < my_array1.length / 2; i++)
  {
    int temp = my_array1[i];
    my_array1[i] = my_array1[my_array1.length - i - 1];
    my_array1[my_array1.length - i - 1] = temp;
  }
    System.out.println("Reverse array : "+Arrays.toString(my_array1));
 }
}

Sample Output:

Original array : [1789, 2035, 1899, 1456, 2013, 1458, 2458, 1254, 1472, 2365, 1456, 2165, 1457, 2456]         
Reverse array : [2456, 1457, 2165, 1456, 2365, 1472, 1254, 2458, 1458, 2013, 1456, 1899, 2035, 1789]

Flowchart:

Flowchart: Java exercises: Reverse an array of integer values

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Java Code Editor:

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Next: Write a Java program to find the duplicate values of an array of integer values.

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Java: Tips of the Day

Different between parseInt() and valueOf() in java?

Well, the API for Integer.valueOf(String) does indeed say that the String is interpreted exactly as if it were given to Integer.parseInt(String). However, valueOf(String) returns a new Integer() object whereas parseInt(String) returns a primitive int.

If you want to enjoy the potential caching benefits of Integer.valueOf(int), you could also use this eyesore:

Integer k = Integer.valueOf(Integer.parseInt("123"))

Now, if what you want is the object and not the primitive, then using valueOf(String) may be more attractive than making a new object out of parseInt(String) because the former is consistently present across Integer, Long, Double, etc.

Ref: https://bit.ly/3vRuIPY