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Java Array Exercises: Convert an array to ArrayList

Java Array: Exercise-20 with Solution

Write a Java program to convert an array to ArrayList.

Pictorial Presentation:

Java Array Exercises:  Convert an array to ArrayList

Sample Solution:

Java Code :

import java.util.ArrayList;
  import java.util.Arrays;
public class Exercise20 {
  public static void  main(String[] args) 
  {
  String[]  my_array = new String[] {"Python", "JAVA", "PHP",  "Perl", "C#", "C++"};
  ArrayList<String>  list = new ArrayList<String>(Arrays.asList(my_array));
  
  System.out.println(list);
  }
}

Sample Output:

[Python, JAVA, PHP, Perl, C#, C++] 

Flowchart:

Flowchart: Java exercises: Convert an array to ArrayList

Visualize Java code execution (Python Tutor):


Java Code Editor:

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Next: Write a Java program to convert an ArrayList to an array.

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Java: Tips of the Day

Different between parseInt() and valueOf() in java?

Well, the API for Integer.valueOf(String) does indeed say that the String is interpreted exactly as if it were given to Integer.parseInt(String). However, valueOf(String) returns a new Integer() object whereas parseInt(String) returns a primitive int.

If you want to enjoy the potential caching benefits of Integer.valueOf(int), you could also use this eyesore:

Integer k = Integer.valueOf(Integer.parseInt("123"))

Now, if what you want is the object and not the primitive, then using valueOf(String) may be more attractive than making a new object out of parseInt(String) because the former is consistently present across Integer, Long, Double, etc.

Ref: https://bit.ly/3vRuIPY