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Java Array Exercises: Find the two elements from a given array of positive and negative numbers such that their sum is closest to zero

Java Array: Exercise-40 with Solution

Write a Java program to find the two elements from a given array of positive and negative numbers such that their sum is closest to zero.

Sample Solution:

Java Code:

import java.util.*;
import java.lang.*;
public class Main
{
   public static void main (String[] args) 
    {
      int arr[] = {1, 5, -4, 7, 8, -6};
      int size = arr.length;
      int l, r, min_sum, sum, min_l_num, min_r_num;
    
      if(size < 2)
      {
        System.out.println("Invalid Input");
        return;
      }
      
      min_l_num = 0;
      min_r_num = 1;
      min_sum = arr[0] + arr[1];
      
      for(l = 0; l < size - 1; l++)
      {
        for(r = l+1; r < size; r++)
        {
          sum = arr[l] + arr[r];
          if(Math.abs(min_sum) > Math.abs(sum))
          {
            min_sum = sum;
            min_l_num = l;
            min_r_num = r;
          }
        }
      }
      
      System.out.println("Two elements whose sum is minimum are "+
                        arr[min_l_num]+ " and "+arr[min_r_num]);
    }
}

Sample Output:

                                                                              
Two elements whose sum is minimum are 5 and -4

Flowchart:

Flowchart: Find the two elements from a given array of positive and negative numbers such that their sum is closest to zero

Visualize Java code execution (Python Tutor):


Java Code Editor:

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Previous: Write a Java program to print all the LEADERS in the array.
Next: Write a Java program to find smallest and second smallest elements of a given array.

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Java: Tips of the Day

Different between parseInt() and valueOf() in java?

Well, the API for Integer.valueOf(String) does indeed say that the String is interpreted exactly as if it were given to Integer.parseInt(String). However, valueOf(String) returns a new Integer() object whereas parseInt(String) returns a primitive int.

If you want to enjoy the potential caching benefits of Integer.valueOf(int), you could also use this eyesore:

Integer k = Integer.valueOf(Integer.parseInt("123"))

Now, if what you want is the object and not the primitive, then using valueOf(String) may be more attractive than making a new object out of parseInt(String) because the former is consistently present across Integer, Long, Double, etc.

Ref: https://bit.ly/3vRuIPY