Java Array Exercises: Arrange the elements of a given array of integers where all positive integers appear before all the negative integers
Java Array: Exercise-49 with Solution
Write a Java program to arrange the elements of a given array of integers where all positive integers appear before all the negative integers.
Pictorial Presentation:

Sample Solution:
Java Code:
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
int arra_nums[] = {-4, 8, 6, -5, 6, -2, 1, 2, 3, -11};
System.out.println("Original array : "+Arrays.toString(arra_nums));
int j,temp,arr_size;
arr_size = arra_nums.length;
for (int i = 0; i <arr_size; i++){
j = i;
//Shift positive numbers left, negative numbers right
while ((j > 0) && (arra_nums[j] >0) && (arra_nums[j-1] < 0)){
temp = arra_nums[j];
arra_nums[j] = arra_nums[j-1];
arra_nums[j-1] = temp;
j--;
}
}
System.out.println("New array : "+Arrays.toString(arra_nums));
}
}
Sample Output:
Original array : [-4, 8, 6, -5, 6, -2, 1, 2, 3, -11] New array : [8, 6, 6, 1, 2, 3, -4, -5, -2, -11]
Flowchart:

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Previous: Write a Java program to arrange the elements of a given array of integers where all negative integers appear before all the positive integers.
Next: Write a Java program to sort an array of positive integers of a given array, in the sorted array the value of the first element should be maximum, second value should be minimum value, third should be second maximum, fourth second be second minimum and so on.
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Java: Tips of the Day
countOccurrences
Counts the occurrences of a value in an array.
Use Arrays.stream().filter().count() to count total number of values that equals the specified value.
public static long countOccurrences(int[] numbers, int value) { return Arrays.stream(numbers) .filter(number -> number == value) .count(); }
Ref: https://bit.ly/3kCAgLb
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