Java Exercises: Reverse a given linked list

Java Basic: Exercise-121 with Solution

Write a Java program to reverse a given linked list.
Example: For linked list 20->40->60->80, the reversed linked list is 80->60->40->20

Pictorial Presentation:

Java Exercises: Reverse a given linked list

Sample Solution:

Java Code:

class LinkedList {

	static Node head;

	static class Node {

		int data;
		Node next_node;

		Node(int d) {
			data = d;
			next_node = null;

	/* Reverse the linked list */
	Node reverse(Node node) {
		Node prev_node = null;
		Node current_node = node;
		Node next_node = null;
		while (current_node != null) {
			next_node = current_node.next_node;
			current_node.next_node = prev_node;
			prev_node = current_node;
			current_node = next_node;
		node = prev_node;
		return node;

	// Prints the elements of the double linked list
	void printList(Node node) {
		while (node != null) {
			System.out.print(node.data + " ");
			node = node.next_node;

	public static void main(String[] args) {
		LinkedList list = new LinkedList();
		list.head = new Node(20);
		list.head.next_node = new Node(40);
		list.head.next_node.next_node = new Node(60);
		list.head.next_node.next_node.next_node = new Node(80);
		System.out.println("Original Linked list:");
		head = list.reverse(head);
		System.out.println("Reversed Linked list:");

Sample Output:

Original Linked list:
20 40 60 80 
Reversed Linked list:
80 60 40 20 


Flowchart: Java exercises: Reverse a given linked list

Java Code Editor:

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Java: Tips of the Day


Counts the occurrences of a value in an array.

Use Arrays.stream().filter().count() to count total number of values that equals the specified value.

public static long countOccurrences(int[] numbers, int value) {
    return Arrays.stream(numbers)
            .filter(number -> number == value)

Ref: https://bit.ly/3kCAgLb