# Java Exercises: Print the area and perimeter of a rectangle

## Java Basic: Exercise-13 with Solution

Write a Java program to print the area and perimeter of a rectangle.

** Java: Perimeter of a rectangle**

A perimeter is a path that surrounds a two-dimensional shape. The word comes from the Greek peri (around) and meter (measure). The perimeter can be used to calculate the length of fence required to surround a yard or garden. Following image represents the perimeter of a rectangle.

**Java: Area of a rectangle**

In Euclidean plane geometry, a rectangle is a quadrilateral with four right angles. To find the area of a rectangle, multiply the length by the width.

A rectangle with four sides of equal length is a square.

Following image represents the area of a rectangle.

**Pictorial Presentation:**

**Sample Solution**:

**Java Code:**

```
public class Exercise13 {
public static void main(String[] strings) {
final double width = 5.6;
final double height = 8.5;
double perimeter = 2*(height + width);
double area = width * height;
System.out.printf("Perimeter is 2*(%.1f + %.1f) = %.2f \n", height, width, perimeter);
System.out.printf("Area is %.1f * %.1f = %.2f \n", width, height, area);
}
}
```

Sample Output:

Perimeter is 2*(8.5 + 5.6) = 28.20 Area is 5.6 * 8.5 = 47.60

**Flowchart: **

**Java Code Editor:**

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## Java: Tips of the Day

**Java: How to round a number to n decimal places in Java**

Use setRoundingMode, set the RoundingMode explicitly to handle your issue with the half-even round, then use the format pattern for your required output.

DecimalFormat df = new DecimalFormat("#.####"); df.setRoundingMode(RoundingMode.CEILING); for (Number n : Arrays.asList(12, 123.12345, 0.23, 0.1, 2341234.212431324)) { Double d = n.doubleValue(); System.out.println(df.format(d)); }

Output:

12 123.1235 0.23 0.1 2341234.2125

For example, when you know that your values are accurate up to 6 digits, then to round half-way values up, add that accuracy to the value:

Double d = n.doubleValue() + 1e-6;

To round down, subtract the accuracy.

Ref: https://bit.ly/3a4mvz0

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