Java: Find the distinct ways you can climb to the top

Java Basic: Exercise-134 with Solution

Distinct Ways to Climb Stairs

Write a Java program to find distinct ways to climb to the top (n steps to reach the top) of stairs. Each time you climb, you can climb 1 or 2 steps.

Example: n = 5 a) 1+1+1+1+1 = 5 b) 1+1+1+2 = 5 c) 1+2+2 = 5 d) 2+2+1 = 5 e) 2+1+1+1 = 5 f) 2+1+2 = 5 g) 1+2+1+1 = 5 h) 1+1+2+1 = 5

Pictorial Presentation:

Sample Solution:

Java Code:

import java.util.*
class Solution {
    // Static method to calculate the distinct ways to climb stairs
    public static int climbStairs(int n) {
        if (n <= 1) {
            return 1; // If there is 0 or 1 step, there is only 1 way to climb.
        }
        int[] s_case = new int[n + 1]; // Create an array to store the number of distinct ways for each step count.
        s_case[0] = 1; // There is 1 way to climb 0 steps.
        s_case[1] = 1; // There is 1 way to climb 1 step.
        for (int i = 2; i <= n; i++) {
            // Calculate the number of distinct ways for each step by adding the ways from the previous two steps.
            s_case[i] = s_case[i - 1] + s_case[i - 2];
        }
        return s_case[n]; // Return the number of distinct ways to climb n steps.
    }

    public static void main(String[] args) {
        int steps = 5; // The number of steps to climb
        System.out.println("Distinct ways can you climb to the top: " + climbStairs(steps));
    }
}

Sample Output:

Distinct ways can you climb to the top: 8

Flowchart:

Java Code Editor:

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