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Java Exercises: Remove all occurrences of a specified value in a given array, return the new length

Java Basic: Exercise-144 with Solution

Write a Java program to remove all occurrences of a specified value in a given array of integers and return the new length of the array.

Pictorial Presentation:

Java Basic Exercises: Remove all occurrences of a specified value in a given array of integers and return the new length of the array.

Sample Solution:

Java Code:

import java.util.*;
public  class Solution {
     /** 
     *@param nums: A list of integers
     *@param element: An integer
     *@return: The new length after remove
     */
  public static int removeElement(int[] nums, int elem) {
      int length = nums.length; 
      if(length==0) return 0; 
      int i=0; 
      for(int j=0; j<length; j++)
      {
        if(nums[j]!=elem)
        {
          nums[i]=nums[j];
          i++; 
        }
      }
      if(i<length) nums[i]='\0';
      return i; 
    }
    public static void main(String[] args) {
		int x = 6;
		int [] nums = {1,4,6,7,6,2};
		System.out.println("Original array: "+Arrays.toString(nums));
        System.out.println("The length of the new array is: " + removeElement(nums, x));
	}		
}

Sample Output:

Original array: [1, 4, 6, 7, 6, 2]
The length of the new array is: 4

Flowchart:

Flowchart: Java exercises: Remove all occurrences of a specified value in a given array of integers and return the new length of the array.

Java Code Editor:

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Java: Tips of the Day

countOccurrences

Counts the occurrences of a value in an array.

Use Arrays.stream().filter().count() to count total number of values that equals the specified value.

public static long countOccurrences(int[] numbers, int value) {
    return Arrays.stream(numbers)
            .filter(number -> number == value)
            .count();
}

Ref: https://bit.ly/3kCAgLb