﻿ Java - Remove all occurrences of a value in an array

# Java: Remove all occurrences of a specified value in a given array, return the new length

## Java Basic: Exercise-144 with Solution

Write a Java program to remove all occurrences of a specified value in a given array of integers. Return the updated array length.

Pictorial Presentation:

Sample Solution:

Java Code:

``````import java.util.*;

public class Solution {
/**
* Remove all occurrences of a given element from an array and return the new length.
* @param nums: A list of integers
* @param element: An integer to be removed
* @return: The new length after removing the element
*/
public static int removeElement(int[] nums, int elem) {
int length = nums.length; // Get the initial length of the array
if (length == 0) return 0; // If the array is empty, return 0 (no changes)

int i = 0; // Initialize the index for the new array

// Iterate through the original array
for (int j = 0; j < length; j++) {
if (nums[j] != elem) {
// If the current element is not equal to the element to be removed
// Copy it to the new position in the array
nums[i] = nums[j];
i++;
}
}

// Replace elements beyond the new length with a sentinel value
if (i < length) nums[i] = '\0';

// Return the new length (the value of 'i')
return i;
}

public static void main(String[] args) {
int x = 6; // Element to be removed
int[] nums = {1, 4, 6, 7, 6, 2}; // Original array
System.out.println("Original array: " + Arrays.toString(nums));

// Call the removeElement function and print the new length
System.out.println("The length of the new array is: " + removeElement(nums, x));
}
}
```
```

Sample Output:

```Original array: [1, 4, 6, 7, 6, 2]
The length of the new array is: 4
```

Flowchart:

Java Code Editor:

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