Java Exercises: Check if a given string is a permutation of another specified string
Java Basic: Exercise-149 with Solution
Write a Java program to check if a given string is a permutation of another given string.
Pictorial Presentation:

Sample Solution:
Java Code:
import java.util.*;
public class Solution {
public static void main(String[] args) {
String str1 = "xxyz";
String str2 = "yxzx";
System.out.println("Original strings: "+str1+" "+str2);
System.out.println(stringPermutation(str1, str2));
}
public static boolean stringPermutation(String str1, String str2) {
int[] arr = new int[500];
for (int i = 0; i < str1.length(); i++) {
arr[(int) str1.charAt(i)] += 1;
}
for (int i = 0; i < str2.length(); i++) {
arr[(int) str2.charAt(i)] -= 1;
}
for (int i = 0; i < arr.length; i++) {
if (arr[i] != 0) return false;
}
return true;
}
}
Sample Output:
Original strings: xxyz yxzx true
Flowchart:

Java Code Editor:
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Previous: Write a Java program to find the index of the first unique character in a given string, assume that there is at least one unique character in the string.
Next: Write a Java program to test if a binary tree is a subtree of another binary tree.
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Java: Tips of the Day
countOccurrences
Counts the occurrences of a value in an array.
Use Arrays.stream().filter().count() to count total number of values that equals the specified value.
public static long countOccurrences(int[] numbers, int value) { return Arrays.stream(numbers) .filter(number -> number == value) .count(); }
Ref: https://bit.ly/3kCAgLb
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