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Java Exercises: Check if a given string is a permutation of another specified string

Java Basic: Exercise-149 with Solution

Write a Java program to check if a given string is a permutation of another given string.

Pictorial Presentation:

Java Basic Exercises: Check if a given string is a permutation of another specified string.

Sample Solution:

Java Code:

import java.util.*;
  public  class  Solution {
    public static void main(String[] args) {
		String str1 = "xxyz";
		String str2 = "yxzx";
		System.out.println("Original strings: "+str1+"  "+str2);
        System.out.println(stringPermutation(str1, str2));
    }
      public static boolean stringPermutation(String str1, String str2) {
        int[] arr = new int[500];
        for (int i = 0; i < str1.length(); i++) {
            arr[(int) str1.charAt(i)] += 1;
        }
        for (int i = 0; i < str2.length(); i++) {
            arr[(int) str2.charAt(i)] -= 1;
        }
        for (int i = 0; i < arr.length; i++) {
            if (arr[i] != 0) return false;
        }
        return true;
    }
}

Sample Output:

Original strings: xxyz  yxzx
true

Flowchart:

Flowchart: Java exercises: Check if a given string is a permutation of another specified string.

Java Code Editor:

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Previous: Write a Java program to find the index of the first unique character in a given string, assume that there is at least one unique character in the string.
Next: Write a Java program to test if a binary tree is a subtree of another binary tree.

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Java: Tips of the Day

countOccurrences

Counts the occurrences of a value in an array.

Use Arrays.stream().filter().count() to count total number of values that equals the specified value.

public static long countOccurrences(int[] numbers, int value) {
    return Arrays.stream(numbers)
            .filter(number -> number == value)
            .count();
}

Ref: https://bit.ly/3kCAgLb