w3resource

Java Exercises: Reverse the content of a sentence without reverse every word

Java Basic: Exercise-169 with Solution

Write a Java program to reverse the content of a sentence (assume a single space between two words) without reverse every word.

Pictorial Presentation:

Java Basic Exercises: Reverse the content of a sentence without reverse every word.

Sample Solution:

Java Code:

import java.util.*;
public class Solution {	
 public static String reverse_str_word(String input_sentence) {
    if (input_sentence == null) {
      throw new IllegalArgumentException("Input param can't be null.");
    }
    StringBuilder stringBuilder = new StringBuilder();
    String[] words = input_sentence.split(" ");
    for (int i = words.length - 1; i >= 0; i--) {
      stringBuilder.append(words[i]);
      if (i != 0) {
        stringBuilder.append(" ");
      }
    }
    return stringBuilder.toString();
  }
   public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.print("Input a string: ");
		String input = scanner.nextLine();
		System.out.println("\nResult: " + reverse_str_word(input));		
		}
}

Sample Output:

Input a string:  The quick brown fox jumps over the lazy dog

Result: dog lazy the over jumps fox brown quick The

Flowchart:

Flowchart: Java exercises: Reverse the content of a sentence without reverse every word.

Java Code Editor:

Contribute your code and comments through Disqus.

Previous: Write a Java program to multiply two given integers without using the multiply operator(*).
Next: Write a Java program to find the length of the longest consecutive sequence of a given array of integers.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.

Java: Tips of the Day

Java: Anagrams

Generates all anagrams of a string.

public static List<String> anagrams(String input) {
    if (input.length() <= 2) {
        return input.length() == 2
                ? Arrays.asList(input, input.substring(1) + input.substring(0, 1))
                : Collections.singletonList(input);
    }
    return IntStream.range(0, input.length())
            .mapToObj(i -> new SimpleEntry<>(i, input.substring(i, i + 1)))
            .flatMap(entry ->
                    anagrams(input.substring(0, entry.getKey()) + input.substring(entry.getKey() + 1))
                            .stream()
                            .map(s -> entry.getValue() + s))
            .collect(Collectors.toList());
}

Ref: https://bit.ly/3rvAdAK