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Java Exercises: Get the number of element that are smaller than the number of another

Java Basic: Exercise-172 with Solution

Write a Java program to get the number of element in a given array of integers that are smaller than the integer of another given array of integers.

Pictorial Presentation:

Java Basic Exercises: Get the number of element that are smaller than the number of another.

Sample Solution:

Java Code:

import java.util.ArrayList;
import java.util.Arrays;
public class Solution {
 public static void main(String[] args) {
 int[] main_arra = {1, 2, 3, 4, 5, 6, 7, 8};
		int[]query_arra = {1, 4, 8};
  ArrayList < Integer > result = count_smaller_number(main_arra, query_arra);
  for (int i = 0; i < result.size(); i++) {
   System.out.println(result.get(i));
  }
 }
 public static ArrayList < Integer > count_smaller_number(int[] main_arra, int[] query_arra) {
  ArrayList < Integer > result = new ArrayList < > ();
  Arrays.sort(main_arra);
  for (int i = 0; i < query_arra.length; i++) {
   result.add(temp(main_arra, query_arra[i]));
  }
  return result;
 }
 private static int temp(int[] main_arra, int num) {
  int ctr = 0;
  for (int i = 0; i < main_arra.length; i++) {
   if (main_arra[i] < num) {
    ctr++;
   } else {
    break;
   }
  }
  return ctr;
 }
}

Sample Output:

0
3
7

Flowchart:

Flowchart: Java exercises: Get the number of element that are smaller than the number of another.

Java Code Editor:

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Previous: Write a Java program to accept two string and test if the second string contains the first one.
Next: Write a Java program to find the median of the number inside the window (size k) at each moving in a given array of intergers with duplicate numbers. Move the window from the start of the array.

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Java: Tips of the Day

Java: Anagrams

Generates all anagrams of a string.

public static List<String> anagrams(String input) {
    if (input.length() <= 2) {
        return input.length() == 2
                ? Arrays.asList(input, input.substring(1) + input.substring(0, 1))
                : Collections.singletonList(input);
    }
    return IntStream.range(0, input.length())
            .mapToObj(i -> new SimpleEntry<>(i, input.substring(i, i + 1)))
            .flatMap(entry ->
                    anagrams(input.substring(0, entry.getKey()) + input.substring(entry.getKey() + 1))
                            .stream()
                            .map(s -> entry.getValue() + s))
            .collect(Collectors.toList());
}

Ref: https://bit.ly/3rvAdAK