﻿ Java: Elements that are smaller than another in an array

# Java Exercises: Get the number of element that are smaller than the number of another

## Java Basic: Exercise-172 with Solution

Write a Java program to get the number of element in a given array of integers that are smaller than the integer of another given array of integers.

Pictorial Presentation: Sample Solution:

Java Code:

``````import java.util.ArrayList;
import java.util.Arrays;
public class Solution {
public static void main(String[] args) {
int[] main_arra = {1, 2, 3, 4, 5, 6, 7, 8};
int[]query_arra = {1, 4, 8};
ArrayList < Integer > result = count_smaller_number(main_arra, query_arra);
for (int i = 0; i < result.size(); i++) {
System.out.println(result.get(i));
}
}
public static ArrayList < Integer > count_smaller_number(int[] main_arra, int[] query_arra) {
ArrayList < Integer > result = new ArrayList < > ();
Arrays.sort(main_arra);
for (int i = 0; i < query_arra.length; i++) {
}
return result;
}
private static int temp(int[] main_arra, int num) {
int ctr = 0;
for (int i = 0; i < main_arra.length; i++) {
if (main_arra[i] < num) {
ctr++;
} else {
break;
}
}
return ctr;
}
}
```
```

Sample Output:

```0
3
7
```

Flowchart: Java Code Editor:

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## Java: Tips of the Day

Java: Anagrams

Generates all anagrams of a string.

```public static List<String> anagrams(String input) {
if (input.length() <= 2) {
return input.length() == 2
? Arrays.asList(input, input.substring(1) + input.substring(0, 1))
: Collections.singletonList(input);
}
return IntStream.range(0, input.length())
.mapToObj(i -> new SimpleEntry<>(i, input.substring(i, i + 1)))
.flatMap(entry ->
anagrams(input.substring(0, entry.getKey()) + input.substring(entry.getKey() + 1))
.stream()
.map(s -> entry.getValue() + s))
.collect(Collectors.toList());
}
```