# Java: Compute the radius and the central coordinate of a circle

## Java Basic: Exercise-218 with Solution

Write a Java program to compute the radius and central coordinates (x, y) of a circle constructed from three given points on the plane surface.

Input:

x1,y1,x2,y2,x3,y3,xp,yp separated by a single space.

Sample Solution:

Java Code:

`````` import java.io.IOException;

class Main {
public static void main(String[] args) throws IOException {
System.out.println("Input x1, y1, x2, y2, x3, y3 separated by a single space:");

double x1 = Double.parseDouble(input);
double y1 = Double.parseDouble(input);
double x2 = Double.parseDouble(input);
double y2 = Double.parseDouble(input);
double x3 = Double.parseDouble(input);
double y3 = Double.parseDouble(input);

double A = x2 - x1;
double B = y2 - y1;
double p = (y2 * y2 - y1 * y1 + x2 * x2 - x1 * x1) / 2;
double C = x3 - x1;
double D = y3 - y1;
double q = (y3 * y3 - y1 * y1 + x3 * x3 - x1 * x1) / 2;

double X = (D * p - B * q) / (A * D - B * C);
double Y = (A * q - C * p) / (A * D - B * C);

double r = Math.sqrt(Math.pow(X - x1, 2.0) + Math.pow(Y - y1, 2.0));
System.out.printf("%.3f (%.3f %.3f)", r, X, Y);
}
}
```
```

Sample Output:

```Input x1, y1, x2, y2, x3, y3 separated by a single space:
5 6 4 8 7 9

1.821 (5.786 7.643)
```

Flowchart: Java Code Editor:

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## Java: Tips of the Day

Capturing an exception's stack trace

```import java.io.*;

Exception e = ...;
java.io.StringWriter sw = new java.io.StringWriter();
e.printStackTrace(new java.io.PrintWriter(sw));
String trace = sw.getBuffer().toString();
```

Ref: https://bit.ly/3k8PmGm

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