# Java: Accepts six numbers as input and sorts them in descending order

## Java Basic: Exercise-221 with Solution

Write a Java program that accepts six numbers as input and sorts them in descending order.

Input:

Input consists of six numbers n1, n2, n3, n4, n5, n6 (-100000 ≤ n1, n2, n3, n4, n5, n6 ≤ 100000). The six numbers are separated by a space.

Visual Presentation: Sample Solution:

Java Code:

``````// Importing necessary Java libraries for input and exception handling
import java.io.IOException;

// Main class named "Main"
public class Main {
// Main method to execute the program
public static void main(String[] args) throws IOException {

// Prompting the user to input six integers
System.out.println("Input six integers:");

// Reading the input line and splitting it into an array of strings
String[] input = br.readLine().split(" ", 6);

// Declaring an array to store the six integers
int[] data = new int;

// Parsing each string in the input array and storing it as an integer in the data array
for (int i = 0; i < 6; i++) {
data[i] = Integer.parseInt(input[i]);
}

// Sorting the integers in descending order using the Bubble Sort algorithm
for (int j = 0; j < 5; j++) {
for (int i = 5; i > j; i--) {
if (data[i - 1] < data[i]) {
// Swapping elements if they are in the wrong order
int swp = data[i];
data[i] = data[i - 1];
data[i - 1] = swp;
}
}
}

// Creating a StringBuilder to build the output string efficiently
StringBuilder sb = new StringBuilder();

// Appending each sorted integer followed by a space to the StringBuilder
for (int i : data) {
sb.append(i);
sb.append(" ");
}

// Displaying the result after sorting the integers
System.out.println("After sorting the said integers:");

// Printing the final output string after removing the trailing space
System.out.println(sb.substring(0, sb.length() - 1));
}
}
```
```

Sample Output:

```Input six integers:
4 6 8 2 7 9
After sorting the said integers:
9 8 7 6 4 2
```

Flowchart: Java Code Editor: