 # Java Exercises: Accepts six numbers as input and sorts them in descending order

## Java Basic: Exercise-221 with Solution

Write a Java program that accepts six numbers as input and sorts them in descending order.

Input:

Input consists of six numbers n1, n2, n3, n4, n5, n6 (-100000 ≤ n1, n2, n3, n4, n5, n6 ≤ 100000). The six numbers are separated by a space.

Pictorial Presentation: Sample Solution:

Java Code:

`````` import java.io.IOException;

public class Main{
public static void main(String[] args) throws IOException {
System.out.println("Input six integers:");
String[] input = br.readLine().split(" ", 6);
int[] data = new int;

for (int i = 0; i < 6; i++) {
data[i] = Integer.parseInt(input[i]);
}

for (int j = 0; j < 5; j++) {
for (int i = 5; i > j; i--) {
if (data[i - 1] < data[i]) {
int swp = data[i];
data[i] = data[i - 1];
data[i - 1] = swp;
}
}
}
StringBuilder sb = new StringBuilder();
for (int i : data) {
sb.append(i);
sb.append(" ");
}
System.out.println("After sorting the said integers:");
System.out.println(sb.substring(0 , sb.length()-1));
}
}
```
```

Sample Output:

```Input six integers:
4 6 8 2 7 9
After sorting the said integers:
9 8 7 6 4 2
```

Flowchart: Java Code Editor: