# Java Exercises: Accepts six numbers as input and sorts them in descending order

## Java Basic: Exercise-221 with Solution

Write a Java program that accepts six numbers as input and sorts them in descending order.

Input:

Input consists of six numbers n1, n2, n3, n4, n5, n6 (-100000 ≤ n1, n2, n3, n4, n5, n6 ≤ 100000). The six numbers are separated by a space.

Pictorial Presentation: Sample Solution:

Java Code:

`````` import java.io.IOException;

public class Main{
public static void main(String[] args) throws IOException {
System.out.println("Input six integers:");
String[] input = br.readLine().split(" ", 6);
int[] data = new int;

for (int i = 0; i < 6; i++) {
data[i] = Integer.parseInt(input[i]);
}

for (int j = 0; j < 5; j++) {
for (int i = 5; i > j; i--) {
if (data[i - 1] < data[i]) {
int swp = data[i];
data[i] = data[i - 1];
data[i - 1] = swp;
}
}
}
StringBuilder sb = new StringBuilder();
for (int i : data) {
sb.append(i);
sb.append(" ");
}
System.out.println("After sorting the said integers:");
System.out.println(sb.substring(0 , sb.length()-1));
}
}
```
```

Sample Output:

```Input six integers:
4 6 8 2 7 9
After sorting the said integers:
9 8 7 6 4 2
```

Flowchart: Java Code Editor:

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

﻿

## Java: Tips of the Day

Java: Anagrams

Generates all anagrams of a string.

```public static List<String> anagrams(String input) {
if (input.length() <= 2) {
return input.length() == 2
? Arrays.asList(input, input.substring(1) + input.substring(0, 1))
: Collections.singletonList(input);
}
return IntStream.range(0, input.length())
.mapToObj(i -> new SimpleEntry<>(i, input.substring(i, i + 1)))
.flatMap(entry ->
anagrams(input.substring(0, entry.getKey()) + input.substring(entry.getKey() + 1))
.stream()
.map(s -> entry.getValue() + s))
.collect(Collectors.toList());
}
```