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Java Exercises: Find the maximum sum of a contiguous subsequence from a given sequence of numbers

Java Basic: Exercise-223 with Solution

Write a Java program to find the maximum sum of a contiguous subsequence from a given sequence of numbers a1, a2, a3, ... an. A subsequence of one element is also a continuous subsequence.

Input:
You can assume that 1 ≤ n ≤ 5000 and -100000 ≤ ai ≤ 100000.
Input numbers are separated by a space.
Input 0 to exit.

Pictorial Presentation:

Java Basic Exercises: Find the maximum sum of a contiguous subsequence from a given sequence of numbers.

Sample Solution:

Java Code:

 import java.util.*;
public class Main {
	public static void main(String [] args) {
		Scanner s = new Scanner(System.in);
		System.out.println("How many integers would you like to input?");
		    int n = s.nextInt();
			int ans = -100000;
			int acc = 0;
			System.out.println("Input the integers:");
			for (int i=0;i<n;i++) {
				acc += s.nextInt();
				ans = Math.max(ans, acc);
				if (acc < 0) acc = 0;
			}
			System.out.println("Maximum sum of the said contiguous subsequence:");
			System.out.println(ans);
		}
}

Sample Output:

How many integers would you like to input?
 5
Input the integers:
 25 61 35 42 66
Maximum sum of the said contiguous subsequence:
229

Flowchart:

Flowchart: Find the maximum sum of a contiguous subsequence from a given sequence of numbers.

Java Code Editor:

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Previous: Write a Java program to test whether two lines PQ and RS are parallel. The four points are P(x1, y1), Q(x2, y2), R(x3, y3), S(x4, y4).
Next: There are two circles C1 with radius r1, central coordinate (x1, y1) and C2 with radius r2 and central coordinate (x2, y2)
Write a Java program to test the followings -
"C2 is in C1" if C2 is in C1
"C1 is in C2" if C1 is in C2
"Circumference of C1 and C2 intersect" if circumference of C1 and C2 intersect, and
"C1 and C2 do not overlap" if C1 and C2 do not overlap.

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Java: Tips of the Day

Java: Anagrams

Generates all anagrams of a string.

public static List<String> anagrams(String input) {
    if (input.length() <= 2) {
        return input.length() == 2
                ? Arrays.asList(input, input.substring(1) + input.substring(0, 1))
                : Collections.singletonList(input);
    }
    return IntStream.range(0, input.length())
            .mapToObj(i -> new SimpleEntry<>(i, input.substring(i, i + 1)))
            .flatMap(entry ->
                    anagrams(input.substring(0, entry.getKey()) + input.substring(entry.getKey() + 1))
                            .stream()
                            .map(s -> entry.getValue() + s))
            .collect(Collectors.toList());
}

Ref: https://bit.ly/3rvAdAK