Java: Accepts an integer (n) and computes the value of n+nn+nnn

Last update on April 27 2023 12:51:12 (UTC/GMT +8 hours)

Java Basic: Exercise-44 with Solution

Write a Java program that accepts an integer (n) and computes the value of n+nn+nnn.

Sample Solution:

Java Code:

import java.util.Scanner;
public class Exercise44 {
 public static void main(String[] args) {

  int n;
  char s1, s2, s3;
  Scanner in = new Scanner(System.in);
  System.out.print("Input number: ");
  n = in .nextInt();
  System.out.printf("%d + %d%d  + %d%d%d\n", n, n, n, n, n, n);
 }
}

Sample Output:

Input number: 5                                                        
5 + 55  + 555

Flowchart:

Java Code Editor:

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Java: Tips of the Day

Handling Null Pointer Exception

Null pointer exception is a runtime exception that is thrown when an application is trying to use an object reference with a null value.

String fruit;
spellChecker(fruit);

Here a null reference variable is passed as an argument of a method.

positionLocator(null);

In the above code snippet, null is directly passed to a function. In both these instances, there is a high possibility of throwing the NullPointerException.

This exception can be fixed by using the if-else condition.

public class NullPointerExceptionExample{
    public static void main(String args[]){
        String fruit = "apple";
        positionLocator(null);
}//Using an if-else condition
    static void positionLocator(String fruit){
        if(fruit != null){
           System.out.println("Second character: "+fruit.charAt(0));
        }
        else {
           System.out.println("NullPointerException thrown");
        }
    }}

Ref: https://bit.ly/3mi39Nr

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