Java: Accepts an integer (n) and computes the value of n+nn+nnn
Java Basic: Exercise-44 with Solution
Write a Java program that accepts an integer (n) and computes the value of n+nn+nnn.
Sample Solution:
Java Code:
import java.util.Scanner;
public class Exercise44 {
public static void main(String[] args) {
int n;
char s1, s2, s3;
Scanner in = new Scanner(System.in);
System.out.print("Input number: ");
n = in .nextInt();
System.out.printf("%d + %d%d + %d%d%d\n", n, n, n, n, n, n);
}
}
Sample Output:
Input number: 5 5 + 55 + 555
Flowchart:

Java Code Editor:
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Java: Tips of the Day
Handling Null Pointer Exception
Null pointer exception is a runtime exception that is thrown when an application is trying to use an object reference with a null value.
String fruit; spellChecker(fruit);
Here a null reference variable is passed as an argument of a method.
positionLocator(null);
In the above code snippet, null is directly passed to a function. In both these instances, there is a high possibility of throwing the NullPointerException.
This exception can be fixed by using the if-else condition.
public class NullPointerExceptionExample{ public static void main(String args[]){ String fruit = "apple"; positionLocator(null); }//Using an if-else condition static void positionLocator(String fruit){ if(fruit != null){ System.out.println("Second character: "+fruit.charAt(0)); } else { System.out.println("NullPointerException thrown"); } }}
Ref: https://bit.ly/3mi39Nr
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