Java Exercises: Accepts an integer and count the factors of the number
Java Basic: Exercise-57 with Solution
Write a Java program to accepts an integer and count the factors of the number.
Sample Solution:
Java Code:
import java.util.*;
public class Exercise57 {
public static void main(String[] args){
Scanner in = new Scanner(System.in);
System.out.print("Input an integer: ");
int x = in.nextInt();
System.out.println(result(x));
}
public static int result(int num) {
int ctr = 0;
for(int i=1; i<=(int)Math.sqrt(num); i++) {
if(num%i==0 && i*i!=num) {
ctr+=2;
} else if (i*i==num) {
ctr++;
}
}
return ctr;
}
}
Sample Output:
Input an integer: 25 3
Pictorial Presentation:

Flowchart:

Java Code Editor:
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Java: Tips of the Day
countOccurrences
Counts the occurrences of a value in an array.
Use Arrays.stream().filter().count() to count total number of values that equals the specified value.
public static long countOccurrences(int[] numbers, int value) { return Arrays.stream(numbers) .filter(number -> number == value) .count(); }
Ref: https://bit.ly/3kCAgLb
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