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Java Exercises: Accepts an integer and count the factors of the number

Java Basic: Exercise-57 with Solution

Write a Java program to accepts an integer and count the factors of the number.

Sample Solution:

Java Code:

import java.util.*;
 public class Exercise57 {
     public static void main(String[] args){
      Scanner in = new Scanner(System.in);
      System.out.print("Input an integer: ");
      int x = in.nextInt(); 

		System.out.println(result(x));
	 } 		
	public static int result(int num) {	
		int ctr = 0;
        for(int i=1; i<=(int)Math.sqrt(num); i++) {
            if(num%i==0 && i*i!=num) {
                ctr+=2;
            } else if (i*i==num) {
                ctr++;
            }
        }
        return ctr;
	}
 }

Sample Output: 

Input an integer: 25                                                   
3

Pictorial Presentation:

Pictorial Presentation: Java exercises: Accepts an integer and count the factors of the number.

Flowchart:

Flowchart: Java exercises: Accepts an integer and count the factors of the number

Java Code Editor:

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Previous: Write a Java program to find the number of integers within the range of two specified numbers and that are divisible by another number.
Next: Write a Java program to capitalize the first letter of each word in a sentence.

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Java: Tips of the Day

Execution of console commands:

Java allows you to execute console commands directly from code using a class Runtime. It is very important not to forget about exception handling.

For example, let's try to open a PDF file through a Java terminal:

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
  
public class ShellCommandExec {
  
  public static void main(String[] args) {
    String gnomeOpenCommand = "gnome-open //home//user//Documents//MyDoc.pdf";
  
    try {
      Runtime rt = Runtime.getRuntime();
      Process processObj = rt.exec(gnomeOpenCommand);
  
      InputStream stdin = processObj.getErrorStream();
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      String myoutput = "";
  
      while ((myoutput=br.readLine()) != null) {
        myoutput = myoutput+"\n";
      }
      System.out.println(myoutput);
    }
    catch (Exception e) {
      e.printStackTrace();
    }
  }
}