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Java Exercises: Accepts an integer and count the factors of the number

Java Basic: Exercise-57 with Solution

Write a Java program to accepts an integer and count the factors of the number.

Sample Solution:

Java Code:

import java.util.*;
 public class Exercise57 {
     public static void main(String[] args){
      Scanner in = new Scanner(System.in);
      System.out.print("Input an integer: ");
      int x = in.nextInt(); 

		System.out.println(result(x));
	 } 		
	public static int result(int num) {	
		int ctr = 0;
        for(int i=1; i<=(int)Math.sqrt(num); i++) {
            if(num%i==0 && i*i!=num) {
                ctr+=2;
            } else if (i*i==num) {
                ctr++;
            }
        }
        return ctr;
	}
 }

Sample Output: 

Input an integer: 25                                                   
3

Pictorial Presentation:

Pictorial Presentation: Java exercises: Accepts an integer and count the factors of the number.

Flowchart:

Flowchart: Java exercises: Accepts an integer and count the factors of the number

Java Code Editor:

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Java: Tips of the Day

countOccurrences

Counts the occurrences of a value in an array.

Use Arrays.stream().filter().count() to count total number of values that equals the specified value.

public static long countOccurrences(int[] numbers, int value) {
    return Arrays.stream(numbers)
            .filter(number -> number == value)
            .count();
}

Ref: https://bit.ly/3kCAgLb