Java Interface: Implement Animal interface with a method bark()

Java Interface: Exercise-2 with Solution

Write a Java program to create a Animal interface with a method called bark() that takes no arguments and returns void. Create a Dog class that implements Animal and overrides speak() to print "Dog is barking".

Sample Solution:

Java Code:

// Animal.java
// Interface Animal

// Declare the Animal interface
public interface Animal {
    // Declare the abstract method "bark" that classes implementing this interface must provide
    void bark();

// Dog.java
// Class Dog

// Declare the Dog class, which implements the Animal interface
public class Dog implements Animal {
    // Implement the "bark" method required by the Animal interface
    public void bark() {
        // Print a message indicating that the Dog is barking
        System.out.println("Dog is barking!");
// Main.java
// Class Main

// Declare the Main class
public class Main {
    public static void main(String[] args) {
        // Create an instance of the Dog class
        Dog dog = new Dog();
        // Call the "bark" method on the Dog instance

Sample Output:

Dog is barking! 


This exercise defines an interface called "Animal" with a method bark() that takes no arguments and returns void. We then define a class called "Dog" that implements the "Animal" interface and overrides the bark() method to print "Dog is barking" to the console.

In the Main class we create an instance of the "Dog" class and call the bark() method, which should print 'Dog is barking' to the console.

Flowchart of Interface Animal:

Flowchart: Interface Animal

Flowchart of Class Dog:

Flowchart: Class Dog

Flowchart of Class Main:

Flowchart: Class Main

Java Code Editor:

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