# Java program to check if a number is a perfect square using lambda expression

## Java Lambda Program: Exercise-18 with Solution

Write a Java program to implement a lambda expression to check if a given number is a perfect square.

Note: A perfect square is an element of algebraic structure that is equal to the square of another element.

**Sample Solution:**

**Java Code:**

```
import java.util.function.Predicate;
public class Main {
public static void main(String[] args) {
// Define the perfect square check lambda expression
Predicate < Integer > isPerfectSquare = n -> {
int sqrt = (int) Math.sqrt(n);
return sqrt * sqrt == n;
};
// Test the lambda expression with some numbers
int N = 36;
boolean result1 = isPerfectSquare.test(N);
System.out.println(N + " is a perfect square? " + result1);
N = 26;
boolean result2 = isPerfectSquare.test(N);
System.out.println(N + " is a perfect square? " + result2);
N = 10000;
boolean result3 = isPerfectSquare.test(N);
System.out.println(N + " is a perfect square? " + result3);
}
}
```

Sample Output:

36 is a perfect square? true 26 is a perfect square? false 10000 is a perfect square? true

**Explanation:**

In the above exercise,

- Import the Predicate functional interface.
- In the main method, we define the lambda expression isPerfectSquare, which takes an integer N.
- The lambda expression checks if the square of the square root of n is equal to n. If it is, then N is a perfect square.
- We test the lambda expression by calling the test method with different numbers.
- Finally, we print the results to the console.

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**Java Lambda Exercises Previous:** Java program to find length of longest and smallest string using lambda expression.

**Java Lambda Exercises Next:** Find second largest and smallest element in an Array.

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