Java: Check whether a number is an Automorphic number or not
Java Numbers: Exercise-14 with Solution
Write a Java program to check whether a number is an automorphic number or not.
In mathematics, an automorphic number is a number whose square "ends" in the same digits as the number itself. For example, 52 = 25, 62 = 36, 762 = 5776, and 8906252 = 793212890625, so 5, 6, 76 and 890625 are all automorphic numbers.
Test Data
Input a number : 76
Pictorial Presentation:
Sample Solution:
Java Code:
import java.util.Scanner;
public class Example14 {
public static void main(String args[])
{
Scanner sc = new Scanner(System.in);
System.out.print("Input a number : ");
int num = sc.nextInt();
int sq_num = num*num;
String str_num = Integer.toString(num);
String square = Integer.toString(sq_num);
if(square.endsWith(str_num))
System.out.println("Automorphic Number.");
else
System.out.println("Not an Automorphic Number.");
}
}
Sample Output:
Input a number : 76 Automorphic Number.
Flowchart:

Java Code Editor:
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Java: Tips of the Day
IsPowerOfTwo
Checks if a value is positive power of two.
To understand how it works let's assume we made a call IsPowerOfTwo(4).
As value is greater than 0, so right side of the && operator will be evaluated.
The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.
The result of (value & value) is value. 100 & 100 => 100.
This will value the expression to true as value is equal to value.
public static boolean isPowerOfTwo(final int value) { return value > 0 && ((value & (~value + 1)) == value); }
Ref: https://bit.ly/3sA5d4I
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