# Java: Check whether a number is an Automorphic number or not

## Java Numbers: Exercise-14 with Solution

Write a Java program to check whether a number is an automorphic number or not.

In mathematics, an automorphic number is a number whose square "ends" in the same digits as the number itself. For example, 5^{2} = 25, 6^{2} = 36, 76^{2} = 5776, and 890625^{2} = 793212890625, so 5, 6, 76 and 890625 are all automorphic numbers.

*Test Data*

Input a number : 76

**Pictorial Presentation:**

**Sample Solution:**

**Java Code:**

```
import java.util.Scanner;
public class Example14 {
public static void main(String args[])
{
Scanner sc = new Scanner(System.in);
System.out.print("Input a number : ");
int num = sc.nextInt();
int sq_num = num*num;
String str_num = Integer.toString(num);
String square = Integer.toString(sq_num);
if(square.endsWith(str_num))
System.out.println("Automorphic Number.");
else
System.out.println("Not an Automorphic Number.");
}
}
```

Sample Output:

Input a number : 76 Automorphic Number.

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**Java Code Editor:**

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## Java: Tips of the Day

**IsPowerOfTwo**

Checks if a value is positive power of two.

To understand how it works let's assume we made a call IsPowerOfTwo(4).

As value is greater than 0, so right side of the && operator will be evaluated.

The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.

The result of (value & value) is value. 100 & 100 => 100.

This will value the expression to true as value is equal to value.

public static boolean isPowerOfTwo(final int value) { return value > 0 && ((value & (~value + 1)) == value); }

Ref: https://bit.ly/3sA5d4I

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