Java: Display first 10 Fermat numbers

Java Numbers: Exercise-20 with Solution

Write a Java program to display the first 10 Fermat numbers.

In mathematics, a Fermat number is a positive integer of the form
Fermat Number
where n is a nonnegative integer.
The first few Fermat numbers are:
3, 5, 17, 257, 65537, 4294967297, 18446744073709551617, …

Pictorial Presentation:

Java: Display first 10 Fermat numbers.

Sample Solution:

Java Code:

import java.util.Scanner;
public class Example20 {
public static void main( String args[] ){ 
        int n = 0;        
        double result;
        while (n <= 10) {
            result= Math.pow (2, Math.pow(2, n)) + 1;
            System.out.println (result);

Sample Output:



Flowchart: Display first 10 Fermat numbers

Java Code Editor:

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Next: Write java program to find any number between 1 and n that can be expressed as the sum of two cubes in two (or more) different ways.

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Java: Tips of the Day


Checks if a value is positive power of two.

To understand how it works let's assume we made a call IsPowerOfTwo(4).

As value is greater than 0, so right side of the && operator will be evaluated.

The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.

The result of (value & value) is value. 100 & 100 => 100.

This will value the expression to true as value is equal to value.

public static boolean isPowerOfTwo(final int value) {
    return value > 0 && ((value & (~value + 1)) == value);

Ref: https://bit.ly/3sA5d4I


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