Java: Display first 10 Fermat numbers
Java Numbers: Exercise-20 with Solution
Write a Java program to display the first 10 Fermat numbers.
In mathematics, a Fermat number is a positive integer of the form
where n is a nonnegative integer.
The first few Fermat numbers are:
3, 5, 17, 257, 65537, 4294967297, 18446744073709551617, …
Pictorial Presentation:
Sample Solution:
Java Code:
import java.util.Scanner;
public class Example20 {
public static void main( String args[] ){
int n = 0;
double result;
while (n <= 10) {
result= Math.pow (2, Math.pow(2, n)) + 1;
n++;
System.out.println (result);
}
}
}
Sample Output:
3.0 5.0 17.0 257.0 65537.0 4.294967297E9 1.8446744073709552E19 3.4028236692093846E38 1.157920892373162E77 1.3407807929942597E154 Infinity
Flowchart:

Java Code Editor:
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Java: Tips of the Day
IsPowerOfTwo
Checks if a value is positive power of two.
To understand how it works let's assume we made a call IsPowerOfTwo(4).
As value is greater than 0, so right side of the && operator will be evaluated.
The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.
The result of (value & value) is value. 100 & 100 => 100.
This will value the expression to true as value is equal to value.
public static boolean isPowerOfTwo(final int value) { return value > 0 && ((value & (~value + 1)) == value); }
Ref: https://bit.ly/3sA5d4I
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