Java: Find and print the first 10 happy numbers
Java Numbers: Exercise-9 with Solution
Write a Java program to find and print the first 10 happy numbers.
Happy number: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1, or it loops endlessly in a cycle which does not include 1.
Example: 19 is a happy number
12 + 92=82
82 + 22=68
62 + 82=100
12 + 02 + 02=1
Pictorial Presentation:
Sample Solution:
Java Code:
import java.util.HashSet;
public class Example9 {
public static void main(String[] args){
System.out.println("First 10 Happy numbers:");
for(long num = 1,count = 0;count<8;num++){
if(happy_num(num)){
System.out.println(num);
count++;
}
}
}
public static boolean happy_num(long num){
long m = 0;
int digit = 0;
HashSet<Long> cycle = new HashSet<Long>();
while(num != 1 && cycle.add(num)){
m = 0;
while(num > 0){
digit = (int)(num % 10);
m += digit*digit;
num /= 10;
}
num = m;
}
return num == 1;
}
}
Sample Output:
First 10 Happy numbers: 1 7 10 13 19 23 28 31
Flowchart:

Java Code Editor:
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Previous: Write a Java program to print out the first 10 Catalan numbers by extracting them from Pascal's triangle.
Next: Write a Java program to check whether a given number is a happy number or unhappy number.
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Java: Tips of the Day
IsPowerOfTwo
Checks if a value is positive power of two.
To understand how it works let's assume we made a call IsPowerOfTwo(4).
As value is greater than 0, so right side of the && operator will be evaluated.
The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.
The result of (value & value) is value. 100 & 100 => 100.
This will value the expression to true as value is equal to value.
public static boolean isPowerOfTwo(final int value) { return value > 0 && ((value & (~value + 1)) == value); }
Ref: https://bit.ly/3sA5d4I
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