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Java: Count the number of decimal places in a given number

Java Regular Expression: Exercise-17 with Solution

Write a Java program to count the number of decimal places in a given number.

Sample Solution-1:

Java Code:

public class test {
 
   public static void main(String[] args) {	   
	   String n = "123";
	   System.out.println("Original Number: "+n);
	   System.out.println("Number of decimal places in the said number: "+validate(n));
	   n = "112.3";
    	   System.out.println("\nOriginal Number: "+n);
	   System.out.println("Number of decimal places in the said number: "+validate(n));
	   n = "112.03";
    	  System.out.println("\nOriginal Number: "+n);
	  System.out.println("Number of decimal places in the said number: "+validate(n));
	  n = "112.233";
    	 System.out.println("\nOriginal Number: "+n);
	 System.out.println("Number of decimal places in the said number: "+validate(n));
        }

   public static Integer validate(String n) {
	   	if(n.contains("."))
			return n.replaceAll(".*\\.(?=\\d?)", "").length();
		return 0;
  }
}

Sample Output: 

Original Number: 123
Number of decimal places in the said number: 0

Original Number: 112.3
Number of decimal places in the said number: 1

Original Number: 112.03
Number of decimal places in the said number: 2

Original Number: 112.233
Number of decimal places in the said number: 3

Pictorial Presentation:

Java Regular Expression: Count the number of decimal places in a given number.

Flowchart :

Flowchart: Count the number of decimal places in a given number.

Sample Solution-2:

Java Code:

public class test {
 
   public static void main(String[] args) {	   
	    String n = "123";
		System.out.println("Original Number: "+n);
		System.out.println("Number of decimal places in the said number: "+validate(n));
		n = "112.3";
    	System.out.println("\nOriginal Number: "+n);
		System.out.println("Number of decimal places in the said number: "+validate(n));
		n = "112.03";
    	System.out.println("\nOriginal Number: "+n);
		System.out.println("Number of decimal places in the said number: "+validate(n));
		n = "112.233";
    	System.out.println("\nOriginal Number: "+n);
		System.out.println("Number of decimal places in the said number: "+validate(n));
        }

   public static Integer validate(String n) {
	   	int ctr = n.indexOf(".");
		return ctr > 0 ? n.length() - ctr - 1 : 0;
  }
}

Sample Output: 

Original Number: 123
Number of decimal places in the said number: 0

Original Number: 112.3
Number of decimal places in the said number: 1

Original Number: 112.03
Number of decimal places in the said number: 2

Original Number: 112.233
Number of decimal places in the said number: 3

Flowchart :

Flowchart: Count the number of decimal places in a given number.

Java Code Editor:

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Java: Tips of the Day

How do I remove repeated elements from ArrayList?

If you don't want duplicates in a Collection, you should consider why you're using a Collection that allows duplicates. The easiest way to remove repeated elements is to add the contents to a Set (which will not allow duplicates) and then add the Set back to the ArrayList:

Set<String> set = new HashSet<>(yourList);
yourList.clear();
yourList.addAll(set);

Of course, this destroys the ordering of the elements in the ArrayList.

Ref: https://bit.ly/3bYIjNC

 

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