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Java Exercises: Find a specified element in a given array of elements using Linear Search

Java Search: Exercise-2 with Solution

Write a Java program to find a specified element in a given array of elements using Linear Search.

Sample Solution:

Java Code:

public class Main {
	static int [] nums;

	public static void main(String[] args) {
		nums = new int[]{3,2,4,5,6,6,7,8,9,9,0,9};
		int result = Linear_Search(nums, 6);
		if(result == -1)
		{
			System.out.print("Not present in the array!");			
		}
		else
		System.out.print("Number found at index "+result);	
	}
	
	private static int Linear_Search(int [] nums,int search)
	{
		for(int i=0;i<nums.length;i++)
		{
			if(nums[i]==search)
			{
				return i;
				
			}			
		}
		return -1;
		
	}
}

Sample Output:

Number found at index 4

Flowchart:

Flowchart: Find a specified element in a given array of elements using Linear Search.

Java Code Editor:

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Next: Write a Java program to find a specified element in a given sorted array of elements using Jump Search.

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Java: Tips of the Day

Array vs ArrayLists:

The main difference between these two is that an Array is of fixed size so once you have created an Array you cannot change it but the ArrayList is not of fixed size. You can create instances of ArrayLists without specifying its size. So if you create such instances of an ArrayList without specifying its size Java will create an instance of an ArrayList of default size.

Once an ArrayList is full it re-sizes itself. In fact, an ArrayList is internally supported by an array. So when an ArrayList is resized it will slow down its performance a bit as the contents of the old Array must be copied to a new Array.

At the same time, it's compulsory to specify the size of an Array directly or indirectly while creating it. And also Arrays can store both primitives and objects while ArrayLists only can store objects.

Ref: https://bit.ly/3o8L2KH