Java String Exercises: Find all interleavings of specified strings

Java String: Exercise-33 with Solution

Write a Java program to find all interleavings of given strings.

Sample Solution:

Java Code:

import java.util.HashSet;
import java.util.Set;

class Main {
 public static void allInterleavings(String res, String P, String Q, Set < String > out) {
  if (P.length() == 0 && Q.length() == 0) {
  if (P.length() > 0) {
   allInterleavings(res + P.charAt(0), P.substring(1), Q, out);
  if (Q.length() > 0) {
   allInterleavings(res + Q.charAt(0), P, Q.substring(1), out);

 public static void main(String[] args) {
  String P = "WX";
  String Q = "YZ";
  System.out.println("The given strings are: " + P + "  " + Q);
  System.out.println("The interleavings strings are: ");
  Set < String > out = new HashSet < > ();
  allInterleavings("", P, Q, out);


Sample Output:

The given strings are: WX  YZ
The interleavings strings are: 


Flowchart: Java String Exercises - Find all interleavings of specified strings

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Java: Tips of the Day

Array vs ArrayLists:

The main difference between these two is that an Array is of fixed size so once you have created an Array you cannot change it but the ArrayList is not of fixed size. You can create instances of ArrayLists without specifying its size. So if you create such instances of an ArrayList without specifying its size Java will create an instance of an ArrayList of default size.

Once an ArrayList is full it re-sizes itself. In fact, an ArrayList is internally supported by an array. So when an ArrayList is resized it will slow down its performance a bit as the contents of the old Array must be copied to a new Array.

At the same time, it's compulsory to specify the size of an Array directly or indirectly while creating it. And also Arrays can store both primitives and objects while ArrayLists only can store objects.

Ref: https://bit.ly/3o8L2KH