w3resource

Java: Rearrange a string so that all same characters become d distance away

Java String: Exercise-47 with Solution

Write a Java program to rearrange a string so that the same characters are positioned a distance away.

Visual Presentation:

Java String Exercises: Rearrange a string so that all same characters become d distance away

Sample Solution:

Java Code:

// Importing necessary Java utilities.
import java.util.*;

// Define a class named Main.
public class Main {

    // Define a constant value for character count.
    public static int MX = 26;

    // Define a class to store character frequency.
    static class freqOfChar {
        char c;
        int f;

        // Constructor for freqOfChar class.
        public freqOfChar(char c, int f) {
            this.c = c;
            this.f = f;
        }
    }

    // Main method to execute the program.
    public static void main(String[] args) {
        String strr = "accessories";
        System.out.println("The given string is: " + strr);
        System.out.println("The string after arranging newly is: ");
        String strg = charRearrange(strr, 4);
        if (strg != null)
            System.out.println(strg);
    }

    // Method to rearrange characters in a string based on frequency and distance k.
    public static String charRearrange(String strg, int k) {
        if (strg.length() <= 1) return strg;

        // Create an array of frequency of characters.
        freqOfChar[] chr_fre = new freqOfChar[MX];
        int ctr = 0;

        // Initialize the frequency array.
        for (int i = 0; i < MX; i++) {
            chr_fre[i] = new freqOfChar((char)('a' + i), 0);
        }

        // Calculate frequency of each character in the string.
        for (int i = 0; i < strg.length(); i++) {
            char ch = strg.charAt(i);
            chr_fre[ch - 'a'].f++;
            if (chr_fre[ch - 'a'].f == 1) ctr++;
        }

        // Build a max heap based on character frequencies.
        bldOfHeap(chr_fre, MX);

        // Create arrays to store rearranged characters and their occurrences.
        char[] str1 = new char[strg.length()];
        boolean[] occu = new boolean[strg.length()];

        // Rearrange characters according to frequency and distance k.
        for (int i = 0; i < ctr; i++) {
            freqOfChar chfreq = extractMax(chr_fre, MX - i);
            int ptr = i;
            while (occu[ptr]) ptr++;

            for (int j = 0; j < chfreq.f; j++) {
                if (ptr >= str1.length)
                    return null;
                str1[ptr] = chfreq.c;
                occu[ptr] = true;
                ptr += k;
            }
        }
        return new String(str1);
    }

    // Method to build a max heap.
    private static void bldOfHeap(freqOfChar[] chr_fre, int size) {
        int i = (size - 1) / 2;
        while (i >= 0) {
            maxHeapify(chr_fre, i, size);
            i--;
        }
    }

    // Method to swap two elements in the frequency array.
    private static void swap(freqOfChar cf1, freqOfChar cf2) {
        char c = cf1.c;
        int f = cf1.f;
        cf1.c = cf2.c;
        cf1.f = cf2.f;
        cf2.c = c;
        cf2.f = f;
    }

    // Method to maintain the max heap property.
    private static void maxHeapify(freqOfChar[] chr_fre, int node, int size) {
        int l = node * 2 + 1;
        int r = node * 2 + 2;
        int largest = node;
        if (l < size && chr_fre[l].f > chr_fre[node].f) {
            largest = l;
        }
        if (r < size && chr_fre[r].f > chr_fre[largest].f) {
            largest = r;
        }
        if (largest != node) {
            swap(chr_fre[node], chr_fre[largest]);
            maxHeapify(chr_fre, largest, size);
        }
    }

    // Method to extract the maximum frequency element from the heap.
    private static freqOfChar extractMax(freqOfChar[] chr_fre, int size) {
        freqOfChar max = chr_fre[0];
        chr_fre[0] = chr_fre[size - 1];
        chr_fre[size - 1] = null;
        maxHeapify(chr_fre, 0, size - 1);
        return max;
    }
}

Sample Output:

The given string is: accessories
The string after arrange newly is: 
secrsecisao

Flowchart: 1

Flowchart: Java String Exercises - Rearrange a string so that all same characters become d distance away

Flowchart: 2

Flowchart: Java String Exercises - Rearrange a string so that all same characters become d distance away

Java Code Editor:

Improve this sample solution and post your code through Disqus

Previous: Write a Java program to reverse every word in a string using methods.
Next: Write a Java program to remove "b" and "ac" from a given string.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Become a Patron!

Follow us on Facebook and Twitter for latest update.

It will be nice if you may share this link in any developer community or anywhere else, from where other developers may find this content. Thanks.

https://www.w3resource.com/java-exercises/string/java-string-exercise-47.php