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Java String Exercises: Find the longest substring appears at both ends of a given string

Java String: Exercise-93 with Solution

Write a Java program to find the longest substring appears at both ends of a given string.

Sample Solution:

Java Code:

import java.util.*;
public class Main
{
public String appearInBothEnds(String stng) 
{
  int l = stng.length();
  String f_str = "";
  String tmp = "";
  for (int i = 0; i < l; i++) 
  {
    tmp += stng.charAt(i);
    int t_len = tmp.length();
    if (i < l / 2 && tmp.equals(stng.substring(l-t_len,l)))
      f_str = tmp;
  }
  return f_str;
}

public static void main (String[] args)
    {
      Main m= new Main();
      String str1 =  "playersplay";
      System.out.println("The given string is: "+str1);
      System.out.println("The longest substring in the string is: "+m.appearInBothEnds(str1));
	  }
}

Sample Output:

The given string is: playersplay
The longest substring in the string is: play

Pictorial Presentation:

Java String Exercises: Find the longest substring appears at both ends of a given string

Flowchart:

Flowchart: Java String Exercises - Find the longest substring appears at both ends of a given string

Java Code Editor:

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Previous: Write a Java program to return a substring after removing the all instances of remove string as given from the given main string.
Next: Write a Java program to find the longest mirror image string at the both ends of a given string.

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Java: Tips of the Day

Array vs ArrayLists:

The main difference between these two is that an Array is of fixed size so once you have created an Array you cannot change it but the ArrayList is not of fixed size. You can create instances of ArrayLists without specifying its size. So if you create such instances of an ArrayList without specifying its size Java will create an instance of an ArrayList of default size.

Once an ArrayList is full it re-sizes itself. In fact, an ArrayList is internally supported by an array. So when an ArrayList is resized it will slow down its performance a bit as the contents of the old Array must be copied to a new Array.

At the same time, it's compulsory to specify the size of an Array directly or indirectly while creating it. And also Arrays can store both primitives and objects while ArrayLists only can store objects.

Ref: https://bit.ly/3o8L2KH