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JavaScript: Get every element that exists in any of the two arrays once

JavaScript fundamental (ES6 Syntax): Exercise-110 with Solution

Write a JavaScript program to get every element that exists in any of the two arrays once.

Note: Create a Set with all values of a and b and convert to an array.

  • Create a new Set() with all values of a and b and convert it to an array.

Sample Solution:

JavaScript Code:

//#Source https://bit.ly/2neWfJ2 
const union = (a, b) => Array.from(new Set([...a, ...b]));
console.log(union([1, 2, 3], [4, 3, 2]));
console.log(union([1, 2, 3], [1, 2, 3]));

Sample Output:

[1,2,3,4]
[1,2,3]

Pictorial Presentation:

JavaScript Fundamental: Get every element that exists in any of the two arrays once.

Flowchart:

flowchart: Get every element that exists in any of the two arrays once

Live Demo:

See the Pen javascript-basic-exercise-110-1 by w3resource (@w3resource) on CodePen.


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JavaScript: Tips of the Day

Chunks an array into n smaller arrays

Example:

const tips_chunkIntoN = (arr, n) => {
  const size = Math.ceil(arr.length / n);
  return Array.from({ length: n }, (v, i) =>
    arr.slice(i * size, i * size + size)
  );
}
console.log(tips_chunkIntoN([1, 2, 3, 4, 5, 6, 7,8], 4));

Output:

[[1,2],[3,4],[5,6],[7,8]]