JavaScript: Get every element that exists in any of the two arrays once
JavaScript fundamental (ES6 Syntax): Exercise-110 with Solution
Write a JavaScript program to get every element that exists in any of the two arrays once.
Note: Create a Set with all values of a and b and convert to an array.
- Create a new Set() with all values of a and b and convert it to an array.
Sample Solution:
JavaScript Code:
//#Source https://bit.ly/2neWfJ2
const union = (a, b) => Array.from(new Set([...a, ...b]));
console.log(union([1, 2, 3], [4, 3, 2]));
console.log(union([1, 2, 3], [1, 2, 3]));
Sample Output:
[1,2,3,4] [1,2,3]
Pictorial Presentation:
Flowchart:

Live Demo:
See the Pen javascript-basic-exercise-110-1 by w3resource (@w3resource) on CodePen.
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Previous: Write a JavaScript program to get the nth element of an given array.
Next: Write a JavaScript program to build an array, using an iterator function and an initial seed value.
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JavaScript: Tips of the Day
Chunks an array into n smaller arrays
Example:
const tips_chunkIntoN = (arr, n) => { const size = Math.ceil(arr.length / n); return Array.from({ length: n }, (v, i) => arr.slice(i * size, i * size + size) ); } console.log(tips_chunkIntoN([1, 2, 3, 4, 5, 6, 7,8], 4));
Output:
[[1,2],[3,4],[5,6],[7,8]]
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